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nlexa [21]
1 year ago
15

A plane is flying to Minnesota with a velocity of 277.73 km/h, N. The plane

Physics
1 answer:
umka2103 [35]1 year ago
7 0

Answer:

466 km/h

255°

measured anticlockwise from the east direction

Explanation:

find the resultant velocity of a plane after a crosswind affects its motion. take the positive

x -direction as east, and the positive y -direction as north. The components of the plane's velocity (without wind) are

  • <em>upx =</em> 0
  • <em>upy =  450 Km/ h</em>

<em>And for the wind.</em>

  • <em>uwx = - 120 Km/h</em>
  • <em>uwy = 0</em>

<em>The components for the r</em><em>esultant velocity </em><em>of the plane are given by</em>

  • <em>ux =upx + uwx = 0 - 120 Km/h =  </em><u><em>- 120 Km/h</em></u>
  • <em>uy = upy + uwy  = - 450 Km/h +0 = </em><u><em>- 450 Km/h</em></u>

<em>The </em><em>magnitude </em><em>of the resultant velocity is</em>

<em />\sqrt{(vx)^2+(vy)^2} =\sqrt{(-120lkm/h^2+(-450lkm/h)^2}

= 466 km/h

Hope this helps u : )

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