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Nookie1986 [14]
2 years ago
10

All rules to find work in changing force in physics ​

Physics
1 answer:
saw5 [17]2 years ago
7 0

Answer:

FORCE - rate of change of momentum, ie its changing velocity [change in velocity is of more concern] NEWTON

WORK - product of force and displacement, ie [velocity may be constant or variable but change in position with certain force is of more concern] JOULES

I hope you understood from this..

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How is the pressure exerted and the area on which it is exerted are related to each other?
andrezito [222]
Pressure = force/area
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4 years ago
What do the top of a zip line and the top of a bungee cord have in common
LiRa [457]

Answer:

They are both placed at high vantage points for an optimal experience.

Explanation:

Gravity works in your favor when participating in bungee jumping as well as ziplining

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a hammer drops from a height of 8 meters. calculate the speed with which it hits the ground. show work
ioda

Answer:

12.5 m/s

Explanation:

The motion of the hammer is a free fall motion, so a uniformly accelerated motion, therefore we can use the following suvat equation:

v^2-u^2=2as

Where, taking downward as positive direction, we have:

s = 8 m is the displacement of the hammer

u = 0 is the initial velocity (it is dropped from rest)

v is the final velocity

a=g=9.8 m/s^2 is the acceleration of gravity

Solving the equation for v, we find the final velocity:

v=\sqrt{u^2+2as}=\sqrt{0+2(9.8)(8)}=12.5 m/s

So, the final speed is 12.5 m/s.

3 0
3 years ago
50 points please help ASAP! !
Contact [7]

Answer:

The sum of the initial and final velocity is divided by 2 to find the average. The average velocity calculator uses the formula that shows the average velocity (v) equals the sum of the final velocity (v) and the initial velocity (u), divided by 2.

4 0
2 years ago
A block is resting on a platform that is rotating at an angular speed of 2.4 rad/s. The coefficient of static friction between t
Sloan [31]

Answer:

r = 0m is the Minimum distance from the axis at which the block can remain in place wothout skidding.

Explanation:

From a sum of forces:

Ff = m*a   where Ff = μ * N    and a = \frac{V^2}{r}=\omega^2*r

N - m*g = 0   So, N = m*g.   Replacing everything on the original equation:

\mu*m*g = m*\omega^2*r   (eq2)

Solving for r:

r = \frac{\mu*g}{\omega^2}=1.41m

If we analyze eq2 you can conclude that as r grows, the friction has to grow (assuming that ω is constant), so the smallest distance would be 0 and the greatest 1.41m. Beyond that distance, μ has to be greater than 0.83.

4 0
3 years ago
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