Answer:
k1 + k2
Explanation:
Spring 1 has spring constant k1
Spring 2 has spring constant k2
After being applied by the same force, it is clearly mentioned that spring are extended by the same amount i.e. extension of spring 1 is equal to extension of spring 2.
x1 = x2
Since the force exerted to each spring might be different, let's assume F1 for spring 1 and F2 for spring 2. Hence the equations of spring constant for both springs are
k1 = F1/x -> F1 =k1*x
k2 = F2/x -> F2 =k2*x
While F = F1 + F2
Substitute equation of F1 and F2 into the equation of sum of forces
F = F1 + F2
F = k1*x + k2*x
= x(k1 + k2)
Note that this is applicable because both spring have the same extension of x (I repeat, EXTENTION, not length of the spring)
Considering the general equation of spring forces (Hooke's Law) F = kx,
The effective spring constant for the system is k1 + k2
<span>During the hour, the second hand will have traveled a full 360 degrees times 60 for a total displacement of 21600 degrees or 21600*pi/180 = 120 pi radians, or approximately 376.99 radians.
Also during that hour, the minute hand will have gone around a full 360 degrees, or 360*pi/180 = 2 pi radians, or approximately 6.28 radians.
And finally, the hour hand will have gone 360/12 = 30 degrees or 30*pi/180 = pi/6 radians, or approximately 0.52 radians.</span>
Answer:
<em>Galvanómetro</em>
Explanation:
Un galvanómetro es un dispositivo eléctrico utilizado para <em>detectar la presencia de corriente y voltaje pequeños o para medir su magnitud.</em> Los galvanómetros se utilizan principalmente en puentes y potenciómetros.
Answer:

Explanation:
The correct formula for the potential energy between two atoms in a particular molecule is:

Where
is the distance.
According to the definitions of potential energy and work, as well as the Work-Energy Theorem and the Principle of Energy Conservation. The relation between that and related force is:

The function is derived in terms of distance:

Then, it is needed to find at least of x so that F(x) equals to 0.



![x=\sqrt[4]{\frac{84}{104} }](https://tex.z-dn.net/?f=x%3D%5Csqrt%5B4%5D%7B%5Cfrac%7B84%7D%7B104%7D%20%7D)

Answer:
(a) Magnitude: 14.4 N
(b) Away from the +6 µC charge
Explanation:
As the test charge has the same sign, the force that the other charges exert on it will be a repulsive force. The magnitude of each of the forces will be:

K is the Coulomb constant equal to 9*10^9 N*m^2/C^2, q and qtest is the charge of the particles, and r is the distance between the particles.
Let's say that a force that goes toward the +6 µC charge is positive, then:


The magnitude will be:
, away from the +6 µC charge