Answer:
(a) 498.4 Hz
(b) 442 Hz
Solution:
As per the question:
Length of the wire, L = 1.80 m
Weight of the bar, W = 531 N
The position of the copper wire from the left to the right hand end, x = 0.40 m
Length of each wire, l = 0.600 m
Radius of the circular cross-section, R = 0.250 mm = 
Now,
Applying the equilibrium condition at the left end for torque:



The weight of the wire balances the tension in both the wires collectively:



Now,
The fundamental frequency is given by:

where

(a) For the fundamental frequency of Aluminium:


where


(b) For the fundamental frequency of Copper:


where


Answer:
coefficient of friction =0.268
magnitude of force P=289.78N
Explanation:
The coefficient of friction is obtained by mgsinФ/mgcosФ=tanФ=tan15=0.268
force P is horizontal as stated in the question, horizontal component of P=mgcosФ=30*10*cos15=289.78
sound travels through a medium in mechanical waves a mechanical wave is a disturbance that moves and transports energy from one place to another through a medium
At -24.613 F<span> temperature is the Fahrenheit scale reading equal to twice that of the Celsius and at </span>160 F<span> temperatuar is the Fahrenheit scale reading equal to half that of the Celsius? So, 160 degrees Celsius will equal 320 degrees Fahrenheit.</span>