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Vikki [24]
3 years ago
5

An injured monkey sits perched on a tree branch 3.0 m above the ground, while a wildlife veterinarian is kneeling down in the bu

shes 87.5 m away attempting to subdue the monkey with a tranquilizer gun. the vet knows that the moment the gun fires the monkey will be frightened and fall down from the branch. what angle up from the ground must the veterinarian aim the gun so that the tranquilizer dart will hit the falling monkey?
Physics
1 answer:
Irina18 [472]3 years ago
6 0

here in the given situation if monkey starts free fall at the same instant when veterinarian shoots towards it then we know that vertical component of motion of monkey and the dart will be same as under gravity

so here the dart will always hit the monkey because they both moves under same acceleration

so here for the angle we can use

tan\theta = \frac{H}{L}

now we have

H = 3 m

L = 87.5 m

now we will have

tan\theta = \frac{3}{87.5}

tan\theta = 0.034

\theta = 1.96 degree

so angle will be 1.96 degree above the ground

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What will be the force if the particle's charge is tripled and the electric field strength is halved? Give your answer in terms
Alexus [3.1K]

Answer:

1.5F

Explanation:

Using

E= F/q

Where F= force

E= electric field

q=charge

F= Eq

So if qis tripled and E is halved we have

F= (E/2)3q

F= 1.5Eq=>> 1.5F

4 0
3 years ago
When the temperature of the air is 25 degress C, the velocity of a sound wave traveling through the air is approximately
dusya [7]
Assuming an ideal gas, the speed of sound depends on temperature 
only.   Air is almost an ideal gas. 

Assuming the temperature of 25°C in a "standard atmosphere", the 
density of air is 1.1644 kg/m3, and the speed of sound is 346.13 m/s. 

The velocity can't be specified, since the question gives no information 
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6 0
3 years ago
1pt A cannon fires a 5-kg ball horizontally from a
Klio2033 [76]

Answer: Both cannonballs will hit the ground at the same time.

Explanation:

Suppose that a given object is on the air. The only force acting on the object (if we ignore air friction and such) will be the gravitational force.

then the acceleration equation is only on the vertical axis, and can be written as:

a(t) = -(9.8 m/s^2)

Now, to get the vertical velocity equation, we need to integrate over time.

v(t) = -(9.8 m/s^2)*t + v0

Where v0 is the initial velocity of the object in the vertical axis.

if the object is dropped (or it only has initial velocity on the horizontal axis) then v0 = 0m/s

and:

v(t) = -(9.8 m/s^2)*t

Now, if two objects are initially at the same height (both cannonballs start 1 m above the ground)

And both objects have the same vertical velocity, we can conclude that both objects will hit the ground at the same time.

You can notice that the fact that one ball is fired horizontally and the other is only dropped does not affect this, because we only analyze the vertical problem, not the horizontal one. (This is something useful to remember, we can separate the vertical and horizontal movement in these type of problems)

7 0
3 years ago
If a dog runs 25m east and then turns around and runs
Nostrana [21]

Answer:

The dog ran a total distance of 45m but he is only 5m away from the starting line

Explanation: When you add 25 to 20 you get 45 for the total distance and if he ran back in the same direction then you would subtract 20 from 25 and get 5m

8 0
2 years ago
A book light has a 1.4 W, 4.8 V bulb that is powered by a transformer connected to a 120 V electric outlet. The secondary coil o
VLD [36.1K]

Answer:

Turns of the primary coil: 500

Current in the primary coil: Ip= 0.01168A

Explanation:

Considering an ideal transformer I can propose the following equations:

        Vp×Ip=Vs×Is

Vp= primary voltaje

Ip= primary current

Vs= secondary voltaje

Is= secondary current

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Np= turns of primary coil

Ns= turns of secondary coil

From these equations I can clear the number of turns of the primary coil:

Np= (Ns×Vp)/Vp = (20×120V)/4.8V = 500 turns

To determine the current in the secondary coil I use the following equation:

Is= (1.4W)/4.8V = 0.292A

Therefore I can determine the current in the primary coil with the following equation:

Ip= (Vs×Is)/Vp = (4.8V×0.292A)/120V = 0.01168A

5 0
3 years ago
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