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3 years ago

Describe the conditions which will cause a rock fracture! Plz hurry

Physics

1 answer:

Naya [18.7K]3 years ago

5 0

Answer:

A fracture will sometimes form a deep fissure or crevice in the rock. Fractures are commonly caused by stress exceeding the rock strength, causing the rock to lose cohesion along its weakest plane. Fractures can provide permeability for fluid movement, such as water or hydrocarbons.

Explanation:

You might be interested in

Briefly describe the difference between the CPC, COC, and CIC certifications. Can you work in a hospital or outpatient facility

madreJ [45]

Answer : the difference between the CPC, COC, and CIC Certified Professional Coder , Certified Outpatient Coder ,Certified Inpatient Coder

Explanation :

CPC - Certified Professional Coder is the gold standerd for medical coding in a physician.

COC - Certified Outpatient Coder is the only standalone outpatient coding credential in the healthcare .

CIC - Certified Inpatient Coder is the only standalone inpatient coding credential in the healthcare .

Yes, we can work in hospital and outpatient facility in COC.

If we have a professional certifications in coding then we can make a best physician.

Yes, credential is important because we can recognize that the doctor works in which field.

4 0

3 years ago

Air conditioners are rated by their coefficient of performance at 61 ∘ F inside temperature and 99 ∘ F outside temperature. An e

vovikov84 [41]

Answer:

the maximum possible coefficient performance is 13.7

Explanation:

inside temperature, $T_{C}$ = 61 F = 289.26 K

outside temperature, $T_{H}$ = 99 F = 310.37 K

coefficient of performance, COP (real) = 3.2

according to Carnot's theorem, the coefficient of performance is

$COP_{max}$ = $\frac{T_{C} }{T_{H}-x_{C} }$

where

$T_{C}$ is cold temperature

$T_{H}$ is hot temperature

thus,

$COP_{max}$ = $\frac{289.26}{310.37-289.26}$

= 13.7

6 0

4 years ago

As the electric current in a lightbulb is slowly increased the filament glows kore and more brightly. Why does this happen

11Alexandr11 [23.1K]

For just a second, think of the light bulb as just a resistance.

The power dissipated any any resistance is (current)² x (resistance).

You can see that if you increase the current through any resistance,
then it dissipates more power.

The light bulb dissipates power in the form of heat and light. If you
increase the current through it, then both of those will increase.

3 0

3 years ago

You discover a new type of microscopic, atom-like object. The energy levels for this object are given by En = E1 n , where E1 =

Studentka2010 [4]

Answer:

a) Excitation energy for the third excited state = -112 eV

b) The amount of energy required to cause an object in the third excited state to become unbound = 112 eV

c) Max number of photons emitted as the object de - excites from the third excited state to the ground state = 6

d) Maximum wavelength photons = 532.286 nm

Minimum wavelength photons = 59.14 nm

Explanation:

From the question, the energy levels are given by $E_{n} = E_{1} n$

Where the energy level for the ground state is given by $E_{1} = -28.0 eV$

a) Excitation energy for the third excited state, n = 4

$E_{4} = 4 * E_{1}$

$E_{4} = -28 * 4$

$E_{4} = -112 eV$

b) The amount of energy required to cause an object in the third excited state to become unbound

$E_{4} = 112 eV$

c) Max number of photons emitted = $\frac{n(n-1)}{2}$

Max number of photons emitted = $\frac{4(4-1)}{2}$

Max number of photons emitted = 2 * 3 = 6

d) $\frac{1}{\lambda_{max} } = \frac{28}{hc} [\frac{1}{3} -\frac{1}{4}]$

$hc = 1242 eV-nm$

$\frac{1}{\lambda_{max} } = \frac{28}{1242} [\frac{1}{3} -\frac{1}{4}]$

$\lambda_{max} = 532.286 nm$

Maximum wavelength photons = 532.286 nm

$\frac{1}{\lambda_{min} } = \frac{28}{hc} [\frac{1}{1} -\frac{1}{4}]$

$\frac{1}{\lambda_{min} } = \frac{28}{1242} [\frac{1}{1} -\frac{1}{4}]$

$\lambda_{min} = 59.14 nm$

Minimum wavelength photons = 59.14 nm

7 0

3 years ago

A train accelerates from rest with as = 1.2 m, for 10 s. After that it moves at constant speed for another 15 s. Please find the

Studentka2010 [4]

Answer:

The total distance covered during the 25 s is 240 m

Explanation:

Hi there!

The position and velocity of the train can be calculated using the following equations:

x = x0 + v0 · t + 1/2 · a · t²

v = v0 + a · t

Where:

x = position at time t

x0 = initial position

v0 = initial velocity

t = time

a = acceleration

v = velocity at time t

When the velocity is constant the position equation is reduced to this expression:

x = x0 + v · t Where "v" is the velocity.

First, let´s calculate the distance traveled during the first 10 s:

x = x0 + v0 · t + 1/2 · a · t²

x = 0 m + 0 m/s · 10 s + 1/2 · 1.2 m/s² · (10 s)²

x = 60 m

The velocity reached after 10 s of acceleration will be:

v = v0 + a · t

v = 0 + 1.2 m/s² · 10 s

v = 12 m/s

Now, we can calculate the distance covered during the next 15 s at constant speed:

x = x0 + v · t

x = 60 m + 12 m/s · 15 s

x = 240 m

The total distance covered during the 25 s is 240 m

Have a nice day!

3 0

3 years ago