Answer:
.25=1.34 seconds
.50=1.89 seconds
Explanation: I got it wrong and those were the correct answers it showed
Answer:
156.24N
Explanation:
From the data above;
Mass = 23g = 0.023kg
V = 88m/s
Kinetic energy = ½mv²
K.e = ½* 0.023 * 88²
K.E = 89.056J
The force required to accelerate the arrow to that speed and energy in 0.57m
Using equation of motion;
V² = U² + 2as
But U =0
V² = 2as
a = v²/2s
a = 88² / (2*0.57)
a = 6792.98m/s²
The force (F) that accelerates the arrow with that velocity = ?
F = M*a
F = 0.023 * 6792.98
F = 156.24N
Answer:
The coefficient of kinetic friction between the puck and the ice is 0.05.
Explanation:
Given that,
Weight of the hockey puck, W = mg = 3.5 N
Acceleration of the hockey puck,
The frictional force opposing the motion of the puck is given by
This force is balanced by the force due to motion of the hockey puck. So,
or
So, the coefficient of kinetic friction between the puck and the ice is 0.05. Hence, this is the required solution.
Answer:
it represents group 2 and also it represents the group 3 stars
Explanation:
because i just took it and got it correct.
Answer:
= 1.132 A
Explanation:
Given that:
A 120-V rms voltage at 60.0 Hz which applied across an inductor, capacitor and a 100- resistor in series.
If the maximum value of the current in this circuit = 1.60 A
what is the rms value of the current in this circuit i.e the = ????
The relation between and can be expressed by the formula:
=
1.60 = 1.414 *
=
= 1.132 A
Thus, the value of the current this circuit = 1.132 A