Question

) A 0.10-kg ball, traveling horizontally at 25 m/s, strikes a wall and rebounds at 19 m/s. What is the magnitude of the change in the momentum of the ball during the rebound?

Answer 1

Answer:

The magnitude of the change in the momentum of the ball during the rebound is 4.4 kg-m/s.

Explanation:

Given that,

Mass of the ball, m = 0.1 kg

Initial speed of the ball, u = 25 m/s

Final speed of the ball, v = -19 m/s (the ball rebounds so it will be negative)

We need to find the magnitude of the change in the momentum of the ball during the rebound. The change in momentum of the object is equal to the difference of final and initial momentum.

$\Delta p=m(v-u)$

$\Delta p=0.1\ kg\times (-19-25)\ m/s$

$\Delta p=-4.4\ kg-m/s$

or

$|\Delta p|=4.4\ kg-m/s$

So, the magnitude of the change in the momentum of the ball during the rebound is 4.4 kg-m/s. Hence, this is the required solution.