Answer:
please the answer below
Explanation:
(a) If we assume that our origin of coordinates is at the position of charge q1, we have that the potential in both points is
![V_1=k\frac{q_1}{r-1.0}-k\frac{q_2}{1.0}=0\\\\V_2=k\frac{q_1}{r+5.2}-k\frac{q_2}{5.2}=0\\\\](https://tex.z-dn.net/?f=V_1%3Dk%5Cfrac%7Bq_1%7D%7Br-1.0%7D-k%5Cfrac%7Bq_2%7D%7B1.0%7D%3D0%5C%5C%5C%5CV_2%3Dk%5Cfrac%7Bq_1%7D%7Br%2B5.2%7D-k%5Cfrac%7Bq_2%7D%7B5.2%7D%3D0%5C%5C%5C%5C)
k=8.89*10^9
For both cases we have
![k\frac{q_1}{r-1.0}=k\frac{q_2}{1.0}\\\\q_1(1.0)=q_2(r-1.0)\\\\r=\frac{q_1+q_2}{q_2}\\\\k\frac{q_1}{r+5.2}=k\frac{q_2}{5.2}\\\\q_1(5.2)=q_2(r+5.2)\\\\r=\frac{5.2q_1-5.2q_2}{q_2}](https://tex.z-dn.net/?f=k%5Cfrac%7Bq_1%7D%7Br-1.0%7D%3Dk%5Cfrac%7Bq_2%7D%7B1.0%7D%5C%5C%5C%5Cq_1%281.0%29%3Dq_2%28r-1.0%29%5C%5C%5C%5Cr%3D%5Cfrac%7Bq_1%2Bq_2%7D%7Bq_2%7D%5C%5C%5C%5Ck%5Cfrac%7Bq_1%7D%7Br%2B5.2%7D%3Dk%5Cfrac%7Bq_2%7D%7B5.2%7D%5C%5C%5C%5Cq_1%285.2%29%3Dq_2%28r%2B5.2%29%5C%5C%5C%5Cr%3D%5Cfrac%7B5.2q_1-5.2q_2%7D%7Bq_2%7D)
(b) by replacing this values of r in the expression for V we obtain
![k\frac{q_1}{\frac{5.2(q_1-q_2)}{q_2}+5.2}=k\frac{q_2}{5.2}\\\\\frac{q_1}{q_2}=\frac{(q_1-q_2)}{q_2}-1.0=\frac{q_1-q_2-q_2}{q_2}=\frac{q_1-2q_2}{q_2}](https://tex.z-dn.net/?f=k%5Cfrac%7Bq_1%7D%7B%5Cfrac%7B5.2%28q_1-q_2%29%7D%7Bq_2%7D%2B5.2%7D%3Dk%5Cfrac%7Bq_2%7D%7B5.2%7D%5C%5C%5C%5C%5Cfrac%7Bq_1%7D%7Bq_2%7D%3D%5Cfrac%7B%28q_1-q_2%29%7D%7Bq_2%7D-1.0%3D%5Cfrac%7Bq_1-q_2-q_2%7D%7Bq_2%7D%3D%5Cfrac%7Bq_1-2q_2%7D%7Bq_2%7D)
hope this helps!!
Answer:
C. 1.04%
Explanation:
The following information has been provided;
Actual density of gold; 19.3 g/cm^3
Observed/measured density of gold; 19.1 g/cm^3
The formula for percent error is given as;
((actual value - observed value)/actual value)) * 100
![\frac{19.3-19.1}{19.3}*100=1.0363](https://tex.z-dn.net/?f=%5Cfrac%7B19.3-19.1%7D%7B19.3%7D%2A100%3D1.0363)
The percent error of the student's measurement is thus 1.04%
Answer: 26.7 s
Explanation:
Given
Width of the river, = 0.2 km = 200 m
Speed of the rover, = 3 m/s
Speed of the boat, = 8 m/s
From the question, the boat would have to move westward. In moving westward, the angle will be
tan A = 3/8
tan A = 0.375
A = tan^-1(0.375)
A = 21°
Then, the velocity of the boat northward will be
v(north) = 8 cos 21
v(north) = 8 * 0.934
v(north) = 7.47 m/s
Therefore, the time taken would be
t = 200/7.47
t = 26.7 s
Answer:
8cm
Explanation:
The general formula to find this is F/X where in this case the f is the total of the two forces (100+100) and x is the sum of the length ( 20+5) which together comes 200&25respectively then divide 200 with 25 which comes 8cm.
The 2 roles of forensic engineers is the detective role and then the engineering role.