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jeka94
3 years ago
5

A swimming pool has the shape of a box with a base that measures 30 m by 10 m and a uniform depth of 2.5 m. How much work is req

uired to pump the water out of the pool when it is​ full? Use 1000 kg divided by m cubed for the density of water and 9.8 m divided by s squared for the acceleration due to gravity.

Physics
2 answers:
alisha [4.7K]3 years ago
8 0

Explanation:

Below is an attachment containing the solution.

pav-90 [236]3 years ago
4 0

Answer:

18,375 kJ

Explanation:

Parameters given:

Density of water: 1000 kg/m³

Acceleration due to gravity = 9.8 m/s²

Dimensions of pool = 30m × 10m × 2.5m

Depth of pool = 2.5 m

First we need to find the mass of the water in the pool:

Density = mass/volume

Mass = density * volume

Since the pool is full of water, the volume of the water is equal to the volume of the pool:

Volume = 30 * 10 * 2.5 = 750 m³

Mass = 1000 * 750

Mass = 750,000 kg

We can now find the force required to pump the water out of the pool:

F = m * g

Where m = mass of water

g = acceleration due to gravity

F = 750,000 * 9.8 = 7,350,000 N

The work needed to be done is the product of the force required by the distance the water would need to move to be pumped out (depth of pool):

Work = F * d

Work = 7,350,000 * 2.5

Work = 18,375,000 J = 18,375 kJ

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You are helping your friend move a new refrigerator into his kitchen. You apply a horizontal force of 275 N in the positive x di
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Answer:

f = 347.08 N

Explanation:

The frictional force exerted by the floor on the refrigerator is given as follows:

f = \mu R = \mu W

where,

f = frictional force = ?

μ = coefficient of static friction = 0.58

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g = acceleration due to gravity = 9.81 m/s²

Therefore,

f = \mu mg\\f = (0.58)(61\ kg)(9.81\ m/s^2)\\

<u>f = 347.08 N</u>

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The four types of musical instruments are percussion, woodwind, brass, and strings.

Explanation:

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A cabbie is trying to stop when he notices a fare is whistling them over. The
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  • K.E=18750J
  • Mass=m=2100kg
  • Velocity=v

\boxed{\sf K.E=\dfrac{1}{2}mv^2}

\\ \sf\longmapsto 18750=\dfrac{1}{2}2100v^2

\\ \sf\longmapsto 18750=1050v^2

\\ \sf\longmapsto v^2=\dfrac{18750}{1050}

\\ \sf\longmapsto v^2=17.85m^2

\\ \sf\longmapsto v=\sqrt{17.85}

\\ \sf\longmapsto v=4.1m/s

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3 years ago
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