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mezya [45]
3 years ago
7

Why is it inaccurate to use mgy to calculate the potential energy of a satellite orbiting earth at a height one earth radius abo

ve the earth's surface
Physics
1 answer:
lubasha [3.4K]3 years ago
7 0
The equation for the force of gravity is F=Gm(planet)m(satellite)/radius(of orbit)^2


Therefore, the square of the distance between the objects (the earth and the satellite) inversely affects the force of gravity on the satellite. This means that the farther apart the objects are, the smaller the force of gravity is (not the constant acceleration of 9.8m/s^2).
You might be interested in
What is the acceleration of an object that has a mass of 10kg and is pushed with a force of 50n
worty [1.4K]

Answer:

5m/s/s

Explanation:

force = mass x acceleration

50 = 10a

a=5m/s/s

7 0
2 years ago
A plate carries a charge of 3.8 UC, while a rod carries a charge of 1.9 C. How many electrons must be transferred from the plate
frosja888 [35]

Answer:

N_{electrons}=Q_{transfered}/q_{electron}=5.94*10^{18}electrons

Explanation:

The total charge is distributed over the two objects:

Q_{total}/2=(3.8*10^{-6}C+1.9C)/2=0.9500019C\\

The plate and the rod must have Q_{total}/2\\. So the charge transferred from the plate to the rod is:

Q_{transfered}=3.8*10^{-6}C-Q_{total}/2=3.8*10^{-6}C-0.9500019C=-0.9499981C\\

Number of electrons:

N_{electrons}=Q_{transfered}/q_{electron}=-0.9499981C/(-1.6*10^{-19}C)=5.94*10^{18}electrons

4 0
2 years ago
Microwave ovens emit microwave energy with a wavelength of 12.2 cm. What is the energy of exactly one photon of this microwave r
Iteru [2.4K]

Answer:

1.63\cdot 10^{-24} J

Explanation:

The energy of a photon is given by:

E=\frac{hc}{\lambda}

where

h is the Planck constant

c is the speed of light

\lambda is the wavelength of the photon

In this problem, we have a microwave photon with wavelength

\lambda=12.2 cm=0.122 m

Substituting into the equation, we find its energy:

E=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{0.122 m}=1.63\cdot 10^{-24} J

5 0
3 years ago
A car of mass m goes around a banked curve of radius r with speed v. If the road is frictionless due to ice, the car can still n
Sholpan [36]

Answer:

horizontal component of normal force is equal to the centripetal force on the car

Explanation:

As the car is moving with uniform speed in circle then the force required to move in the circle is towards the center of the circle

This force is due to friction force when car is moving in circle with uniform speed

Now it is given that car is moving on the ice surface such that the friction force is zero now

so here we can say that centripetal force is due to component of the normal force which is due to banked road

Now we have

N sin\theta = \frac{mv^2}{R}

N cos\theta = mg

so we have

v = \sqrt{Rg tan\theta}

so this is horizontal component of normal force is equal to the centripetal force on the car

5 0
3 years ago
Explain in your own words how volume is measured.
pav-90 [236]

Answer:

volume measured by pid^3 over 6 i think

Explanation:

7 0
3 years ago
Read 2 more answers
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