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3 years ago

Electron Identify the type of charge of the following particles in an

Chemistry

1 answer:

Alexeev081 [22]3 years ago

5 0

Answer:

Electron charge: -1

Neutron charge: 0

Proton charge: +1

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If an atom of Phosphorous has 17 neutrons, what is its mass number?

Alina [70]

Mass number = number of protons + number of neutrons

The number of protons in the nucleus of an atom of phosphorus is equal to the atomic number of phosphorus, which is 15. If an atom of phosphorus has 17 neutrons, then the mass number would be 15 protons + 17 neutrons = 32. Thus, the correct answer choice here is B.

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2 years ago

What is the correct definition of Earth's energy budget?

ollegr [7]

Answer:

Earth's energy budget describes the balance between the radiant energy that reaches Earth from the sun and the energy that flows from Earth back out to space

Explanation:

i hope it helps you

have a nice day,❤️

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2 years ago

Read 2 more answers

A chemist prepares a solution of copper(II) fluoride by measuring out of copper(II) fluoride into a volumetric flask and filling

Simora [160]

The question is incomplete, here is the complete question.

A chemist prepares a solution of copper(II) fluoride by measuring out 0.0498 g of copper(II) fluoride into a 100.0mL volumetric flask and filling the flask to the mark with water.

Calculate the concentration in mol/L of the chemist's copper(II) fluoride solution. Round your answer to 3 significant digits.

<u>Answer:</u> The concentration of copper fluoride in the solution is $4.90\times 10^{-3}mol/L$

<u>Explanation:</u>

To calculate the molarity of solute, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Given mass of copper (II) fluoride = 0.0498 g

Molar mass of copper (II) fluoride = 101.54 g/mol

Volume of solution = 100.0 mL

Putting values in above equation, we get:

$\text{Molarity of copper (II) fluoride)=\frac{0.0498\times 1000}{101.54\times 100.0}\\\\\text{Molarity of copper (II) fluoride}=4.90\times 10^{-3}mol/L$

Hence, the concentration of copper fluoride in the solution is $4.90\times 10^{-3}mol/L$

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3 years ago

In general, non-spontaneous reactions __________.

Rom4ik [11]

Very low gives free energy

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3 years ago

A mixture of propane and butane is burned with pure oxygen. The combustion products contain 46.7 mole% H2O. After all the water

wlad13 [49]

Answer:

28%

Explanation:

Basically, all o did was write the equations, balance it and solve for them. Also, at the place I stared, I used simultaneous equation to solve it. Multiplying by 8 and also 3.

It's a pretty straightforward question.

At the final step that's missing, I Did

(y)C3H8 = 2.8 / ( 2.8 + 7.1)

(y)C3H8 = 0.28

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2 years ago