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3 years ago

Rank in order, from smallest to largest, the six torques (torque 1 to torque 2) about the hinge.?

1 answer:

5 0

The solution for this problem is:torque1 = torque2 = FL / 2
Torque 3 = Torque 4 = FL / 2 * sin (theta)
Torque 5 = 2 FL
Torque 6 = 0

So the order of the torques from smallest to largest is torque 6, (torque 3 and 4), (torque 1 and 2), torque 5.

Remember or just take note that sin (theta) < 1 is why 3 and 4 are less than 1 and 2.

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Find then circumference

Keith_Richards [23]

Answer:

A. 13 cm

Explanation:

here the total diameter is given 4 cm,

here the radius then will be 2 cm.

use the formula of circumference of circle = 2πr ........where r is the radius

using the formula: 2 * π * 2 = 4π = 12.57 = 13 cm.

5 0

2 years ago

You’ll get 100 points for answering this quick question

Elena-2011 [213]

Answer: D

Explanation:

Insolation means incoming solar radiation. It is the amount of incoming solar radiation that is received per unit area of the earth’s surface.

At any point except D, insolation is lesser because sun radiation is more spread out and as a result less solar radiation is received per unit area of the earth’s surface.

So, choice D is the correct answer.

4 0

3 years ago

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Thermal physics vs atomic physics ...which is easier?

Tanya [424]

Answer:

Thermal physics

Explanation:

Because it uses temperature

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3 years ago

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A race car has a mass of 710 kg. It starts from rest and travels 40 m in 3.0 s. The car is uniformly accelerated during the enti

Archy [21]

The net force applied to it is 6311.9 N.

To calculate the net force to the car, first, we need to find the acceleration using the equation of motion.

Force: This as be defined as the product of mass and acceleration of a body. The S.I unit of force is Newton (N)

⇒ Formula

S = ut+at²/2................. Equation 1

⇒ Where:

u = Initial velocity
S = Distance
t = Time
a = acceleration

From the question,

⇒Given:

S = 40 m
t = 3.0 s
u = 0 m/s (at rest)

⇒ Substitute these values into equation 1

40 = 0(3)+a(3²)/2

⇒ Solve for a

9a = 80
a = 80/9
a = 8.89 m/s²

⇒ To get the force, we use the formula below

F = ma .................... Equation 2

⇒ Where:

F = Force applied
m = mass of the car

⇒ Given:

m = 710 kg
a = 8.89 m/s²

⇒ Substitute these values into equation 2

F = 710(8.89)

F = 6311.9 N

Hence the net force applied to it is 6311.9 N.

Learn more about force here: brainly.com/question/13370981

6 0

2 years ago

A soccer ball of diameter 22.6cm and mass 426g rolls up a hill without slipping, reaching a maximum height of 5m above the base

-Dominant- [34]

Answer with Explanation:

We are given that

Diameter=d=22.6 cm

Mass,m=426 g= $426\times 10^{-3} kg$

1 kg=1000 g

Radius,r= $\frac{d}{2}=\frac{22.6}{2}=11.3 cm=11.3\times 10^{-2} m$

1m=100 cm

Height,h=5m

$I=\frac{2}{2}mr^2$

a.By law of conservation of energy

$\frac{1}{2}I\omega^2+\frac{1}{2}mv^2=mgh$

$\frac{1}{2}\times \frac{2}{3}mr^2\omega^2+\frac{1}{2}mr^2\omega^2=mgh$

$v=\omega r$

$gh=\frac{1}{3}r^2+\frac{1}{2}r^2=\frac{5}{6}r^2\omega^2$

$\omega^2=\frac{6}{5r^2}gh$

$\omega=\sqrt{\frac{6gh}{5r^2}}=\sqrt{\frac{6\times 9.8\times 5}{5(11.3\times 10^{-2})^2}}=67.86 rad/s$

Where $g=9.8m/s^2$

b.Rotational kinetic energy= $\frac{1}{2}I\omega^2=\frac{1}{2}\times \frac{2}{3}mr^2\omega^2=\frac{1}{2}\times \frac{2}{3}(426\times 10^{-3})(11.3\times 10^{-2})^2(67.86)^2=8.35 J$

Rotational kinetic energy=8.35 J

6 0

3 years ago