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3 years ago

Rank in order, from smallest to largest, the six torques (torque 1 to torque 2) about the hinge.?

1 answer:

5 0

The solution for this problem is:torque1 = torque2 = FL / 2
Torque 3 = Torque 4 = FL / 2 * sin (theta)
Torque 5 = 2 FL
Torque 6 = 0

So the order of the torques from smallest to largest is torque 6, (torque 3 and 4), (torque 1 and 2), torque 5.

Remember or just take note that sin (theta) < 1 is why 3 and 4 are less than 1 and 2.

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In a shipping company distribution center, an open cart of mass 50.0 kg is rolling to the left at a speed of 5.00 m/s. Ignore fr

spin [16.1K]

Answer:

a) $v_p=9.35m/s$

Explanation:

From the question we are told that:

Open cart of mass $M_o=50.0 kg$

Speed of cart $V=5.00m/s$

Mass of package $M_p=15.0kg$

Speed of package at end of chute $V_c=3.00m/s$

Angle of inclination $\angle =37$

Distance of chute from bottom of cart $d_x=4.00m$

Generally the equation for work energy theory is mathematically given by

$\frac{1}{2}mu^2+mgh=\frac{1}{2}mv_p^2$

Therefore

$\frac{1}{2}u^2+gh=\frac{1}{2}v_p^2$

$v_p=\sqrt{2(\frac{1}{2}u^2+gh)}$

$v_p=\sqrt{2(\frac{1}{2}v_c^2+gd_x)}$

$v_p=\sqrt{2(\frac{1}{2}(3)^2+(9.8)(4))}$

$v_p=9.35m/s$

4 0

2 years ago

The most effective way to process biodiversity is through

lidiya [134]

I suppose it's C. All the other answers are everything but accurate to me

6 0

3 years ago

Two sources of light of wavelength 720 nm are 10 m away from a pinhole of diameter 1.2 mm. How far apart must the sources be for

julia-pushkina [17]

Answer:

The value is $y = 0.00732 \ m$

Explanation:

From the question we are told that

The wavelength of each source is $\lambda = 720 \ nm = 720 *10^{-9} \ m$

The distance from the pinhole $D = 10 \ m$

The diameter is $d = 1.2 mm = \frac{1.2}{1000} = 0.0012 \ m$

Generally from Rayleigh's criterion we have that the distance between the sources of light for their diffraction patterns is mathematically represented as '

$y = \frac{ 1.22 * \lambda * D}{d}$

=> $y = \frac{ 1.22 * 720 *10^{-9}* 10 }{ 0.0012}$

=> $y = 0.00732 \ m$

6 0

3 years ago

A stone is thrown from the top of a building 30m high. If it strikes the ground at an angle 45, with what speed was it thrown?

sasho [114]

Answer:

24.2 m/s

Explanation:

The stone strikes the ground at an angle of 45 degrees: this means that its vertical velocity is equal (in magnitude) to its horizontal velocity, in fact:

$tan \theta = \frac{|v_y|}{v_x}\\tan 45^{\circ} = 1 \rightarrow |v_y| = v_x$

The motion along the vertical direction is a uniformly accelerated motion, so we can find the final vertical velocity using the following suvat equation

$v_y^2 -u_y^2 = 2as$

where

$v_y$ is the final vertical velocity

$u_y = 0$ is the initial vertical velocity (zero because the stone is thrown horizontally)

$a=g=9.8 m/s^2$ is the acceleration of gravity (we take downward as positive direction)

s = 30 m is the vertical displacement

Solving for vy,

$v_y = \sqrt{u_y^2+2as}=\sqrt{0+2(9.8)(30)}=24.2 m/s$

This means that the horizontal velocity is also 24.2 m/s: and since the horizontal velocity is constant during the whole motion (there is no acceleration in the horizontal direction), this means that the stone was thrown exactly at 24.2 m/s.

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3 years ago

Which pm the following are likely to form a covalent bond

Alecsey [184]

Answer:

magneisuim and gold

Explanation:

8 0

3 years ago

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