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3 years ago

Rank in order, from smallest to largest, the six torques (torque 1 to torque 2) about the hinge.?

1 answer:

5 0

The solution for this problem is:torque1 = torque2 = FL / 2
Torque 3 = Torque 4 = FL / 2 * sin (theta)
Torque 5 = 2 FL
Torque 6 = 0

So the order of the torques from smallest to largest is torque 6, (torque 3 and 4), (torque 1 and 2), torque 5.

Remember or just take note that sin (theta) < 1 is why 3 and 4 are less than 1 and 2.

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The interference pattern seen when light passes through narrow, closely spaced slits, is due to

Lelu [443]

<h2>Answer: Diffraction</h2><h2 />

Diffraction is a characteristic phenomenon that occurs in all types of waves .

In this sense, <u>diffraction</u> happens when a wave (the light in this case) meets an obstacle or a slit .When this occurs, the light bends around the corners of the obstacle or passes through the opening of the slit that acts as an obstacle, forming <u><em>multiple patterns</em></u> with the shape of the aperture of the slit.

Note that the principal condition for the occurrence of this phenomena is that <u>the obstacle must be comparable in size (similar size) to the size of the wavelength. </u>

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8 0

4 years ago

What is the acceleration of a 59 kg object pushed with a force of 500 Newton's ?

Igoryamba

Answer:

a=500/50=10 m/s^2

Explanation:

f=m•a a=f/m

a=500/50= 10 m/s^2

4 0

3 years ago

Two objects, with different sizes, masses, and temperatures, are placed in thermal contact. in which direction does the energy t

s344n2d4d5 [400]

<span>(c) energy travels from the object at higher temperature
to the object at lower temperature.

Size and mass have no effect.</span>

3 0

3 years ago

3. A motorbike travels 45 miles in 15 minutes, what is its speed?

antiseptic1488 [7]

Hes going 180 mph
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3 0

3 years ago

A 1.70 m tall woman stands 5.00 m in front of a camera with a 50.00 cm focal

slamgirl [31]

Answer:

18.89cm

Explanation:

As we know that the person is standing 5m in front of the camera

$d_0=5m=500cm$

The focal length of the lens =50cm

f=50 cm

By Lens formula we have:

$\dfrac{1}{f} = \dfrac{1}{d_i} + \dfrac{1}{d_o}\\\dfrac{1}{50} = \dfrac{1}{d_i} + \dfrac{1}{500}\\\dfrac{1}{d_i} =\dfrac{1}{50}-\dfrac{1}{500}\\\dfrac{1}{d_i}=0.018\\d_i=55.56cm$

By the formula of magnification

$\dfrac{h_i}{h_o} = \dfrac{55.56}{500}\\\\h_i = \dfrac{55.56}{500} \times h_o\\\\ h_o=1.70m=170cm\\\\Therefore: h_i=\dfrac{55.56}{500} \times$ 170 cm\\\\h_i =18.89 cm$

The height of the image formed is 18.89cm.

5 0

3 years ago