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3 years ago

Why is there no answer

Chemistry

2 answers:

kogti [31]3 years ago

7 0

You can just ask what your question is and people reply if hey know the anwser hope this helps lol

denis23 [38]3 years ago

5 0

Answer:

i don't know

Explanation:

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Normal body temperature is 98.6 degrees fahrenheit is what degrees Celsius

anyanavicka [17]

Answer: 37

Explanation:

8 0

4 years ago

Read 2 more answers

Please answer this.A) ____ N2 + ____ H2 → ____ NH3B) ____ KClO3 → ____ KCl + ____ O2C) ____ NaCl + ____ F2 → ____ NaF + ____ Cl2

Lady_Fox [76]

1) Decomposition reactions. In this type of reaction, a compound is broken down into simpler compounds.

$AB\rightarrow A+B$

Option B is a decomposition reaction

B) ____ KClO3 → ____ KCl + ____ O2

8 0

1 year ago

Since both HBr and KOH are strong, we expect these reactions to occur fully. You mix 2 moles of HBr with 3 moles of KOH in enoug

AysviL [449]

Answer: pH = 14

Explanation: Please see the attachments below

8 0

3 years ago

Gaseous methane (CH4) reacts with gaseous oxygen gas (02) to produce gaseous carbon dioxide (CO2) and gaseous water (H20). What

Mariana [72]

Answer:

Theoretical yield = 3.51 g

Explanation:

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

For $CH_4$ :-

Mass of $CH_4$ = 1.28 g

Molar mass of $CH_4$ = 16.04 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{1.28\ g}{16.04\ g/mol}$

$Moles_{CH_4}= 0.0798\ mol$

For $O_2$ :-

Mass of $O_2$ = 10.1 g

Molar mass of $O_2$ = 31.998 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{10.1\ g}{31.998\ g/mol}$

$Moles_{O_2}= 0.3156\ mol$

According to the given reaction:

$CH_4+2O_2\rightarrow CO_2+2H_2O$

1 mole of methane gas reacts with 2 moles of oxygen gas

0.0798 mole of methane gas reacts with 2*0.0798 moles of oxygen gas

Moles of oxygen gas = 0.1596 moles

Available moles of oxygen gas = 0.3156 moles

<u>Limiting reagent is the one which is present in small amount. Thus, $CH_4$ is limiting reagent. </u>

The formation of the product is governed by the limiting reagent. So,

1 mole of methane gas on reaction produces 1 mole of carbon dioxide.

0.0798 mole of methane gas on reaction produces 0.0798 mole of carbon dioxide.

Mole of carbon dioxide = 0.0798 mole

Molar mass of carbon dioxide = 44.01 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$0.0798\ moles= \frac{Mass}{44.01\ g/mol}$

Mass of $CO_2$ = 3.51 g

<u> Theoretical yield = 3.51 g</u>

3 0

3 years ago

hat is the percentage of water in the following compound? Answer using three significant figures. Sodium carbonate decahydrate,

BigorU [14]

You need to find the whole molar mass of the compound using the periodic table to add the values.

Na2CO3= (2 x 23.0) + 12.0 + (3 x 16.0)= 106 g/mol
H2O= 10 x [ (2 x 1.01 ) + (16.0) ]= 180.2 g/mol

the total molar mass is 106 + 180.2 = 286.2 g/mol

the percentage of water you can find by doing "parts over the whole"

H2O%= 180.2 / 286.2 X 100= 63.0%

7 0

3 years ago