Multiply 9.0g/cm3 by 0.31g = 2.79cm3
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1) The amount of PbS produced will be 16.27 grams
2: The amount of Fe produced will be 118.72 grams.
<h3>Stoichiometric problems</h3>
1) The equation is balanced. The mole ratio of lead (II) acetate to the PbS is 1:1.
Mole of 22.11 lead acetate = 22.11/ 325.29 = 0.06797 moles
Equivalent mole of PbS = 0.06797 moles
Mass of PbS = 0.06797 x 239.3 = 16.27 grams
2) from the equation, the mole ratio of Al to Fe is 1:1.
Mole of 57.2 g Al = 57.2/26.98 = 2.12 moles
Equivalent mole of Fe = 2.12 moles
Mass of Fe = 2.12 x 56 = 118.72 grams.
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Density=mass/volume
density=45/26.4
density=1.7g/ml
