Answer:
The most reactive group of elements are found in group 1 which are alkali metals.
Explanation:
The reason why they are so reactive is because they only electron in the outer shell so this causes the to lose that one electron in ionic bonding with other elements.
0.014 mol of gas undergoes the process shown in the figure (Figure 1) .
Answer:
Conociendo el volumen de solución, masa de soluto y su masa molar, es posible determinar: B) Concentración molar
La molaridad es la relación entre el número de moles de soluto y los litros de solución. Más:
M = No moles de solución de soluto / volumen (L)
Y a su vez los moles de soluto se encuentran por:
No moles de soluto = masa soluto / masa molar soluto
The bowling ball because it has more weight but it could be the marble
Answer:
CaCl₂
Step-by-step explanation:
The <em>empirical formula</em> is the simplest whole-number ratio of atoms in a compound.
The ratio of atoms is the same as the ratio of moles.
So, our job is to calculate the molar ratio of Ca to Cl.
Data:
Mass of Ca = 3.611 g
Mass of Cl = 6.389 g
Calculations
Step 1. <em>Calculate the moles of each element
</em>
Moles of Ca = 3.611 g Ca × (1 mol Ca/(40.08 g Ca)= 0.090 10 mol Ca
Moles of Cl = 6.389 g Cl
Step 2. <em>Calculate the molar ratio of the elements
</em>
Divide each number by the smallest number of moles
Ca:Cl = 0.090 10:0.1802 = 1:2.000
Step 3. Round the molar ratios to the nearest integer
Ca:Cl = 1:2.000 ≈ 1:2
Step 4: <em>Write the empirical formula
</em>
EF = CaCl₂
