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brilliants [131]
3 years ago
6

Here are some energy resources. List the renewable energy resources.

Physics
2 answers:
Artemon [7]3 years ago
3 0
Solar wind geothermal
Pavel [41]3 years ago
3 0
Solar and Geothermal
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A high-jump athlete leaves the ground, lifting her center of mass 1.8 m and crossing the bar with a horizontal velocity of 1.4 m
Romashka [77]

Answer:

The minimum speed when she leave the ground is 6.10 m/s.

Explanation:

Given that,

Horizontal velocity = 1.4 m/s

Height = 1.8 m

We need to calculate the minimum speed must she leave the ground

Using conservation of energy

K.E+P.E=P.E+K.E

\dfrac{1}{2}mv_{1}^2+0=mgh+\dfrac{1}{2}mv_{2}^2

\dfrac{v_{1}^2}{2}=gh+\dfrac{v_{2}^2}{2}

Put the value into the formula

\dfrac{v_{1}^2}{2}=9.8\times1.8+\dfrac{(1.4)^2}{2}

\dfrac{v_{1}^2}{2}=18.62

v_{1}=\sqrt{2\times18.62}

v_{1}=6.10\ m/s

Hence, The minimum speed when she leave the ground is 6.10 m/s.

6 0
3 years ago
A container of gas molecules is at a pressure of 2 atm and has amass density of 1.7 grams per liter. All of the molecules in the
Tpy6a [65]

Answer:

The speed of nitrogen molecule is 1.87 m/s.

Explanation:

Given that,

Pressure = 2 atm

Density = 1.7 grams/liter

Atomic weight = 28 grams

We need to calculate the temperature

Using formula of idea gas

PV=nRT

P=\dfrac{WRT}{VM}

P=\dfrac{\rho RT}{M}

T=\dfrac{PM}{\rho R}

Put the value into the formula

T=\dfrac{2\times28}{1.7\times0.0821}

T=401.2\ K

We need to calculate the speed of nitrogen molecule

Using formula of RMS speed

V_{rms}=\sqrt{\dfrac{3RT}{M}}

V_{rms}=\sqrt{\dfrac{3\times0.0821\times401.2}{28}}

V_{rms}=1.87\ m/s

Hence, The speed of nitrogen molecule is 1.87 m/s.

5 0
3 years ago
Ahmad was moving to the south with v= 10 km/hr ,and Mohammed was moving with half of Ahmad's speed to the North . Write the vect
mafiozo [28]

Answer:

5 north

Explanation:

7 0
3 years ago
A charged particle is observed traveling in a circular path in a uniform magnetic field. If the particle had been traveling four
8090 [49]

Answer:

The new radius of the trajectory of the particle is four times the previous radius

Explanation:

In order to know what is the radius of the trajectory of the charged particle, if its speed is four times as fast, you take into account the following formula, which describes the radius of a charged particle in a magnetic field:

r=\frac{mv}{qB}          (1)

If the speed of the particle is for time as fast, that is, v' = 4v, you obtain, in the equation (1):

r'=\frac{mv'}{qB}=\frac{m(4v)}{qB}=4\frac{mv}{qB}=4r

The new radius of the trajectory of the particle is four times the previous radius

8 0
3 years ago
Sound travels slowest through what temperature of water?.
natta225 [31]

Answer:

20 degrees.

Explanation:

this is my answer hope that I will help you

4 0
2 years ago
Read 2 more answers
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