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MissTica
2 years ago
8

Which statement explains whether or not a person should use an experiment of a ball rolling down a hill as evidence that the for

ce of gravity pulls objects straight down?(1 point) They should use it. Any experiment on Earth involving natural motion will provide direct evidence that gravity pulls objects straight down. They should use it. Any experiment on Earth involving natural motion will provide direct evidence that gravity pulls objects straight down. They should not use it. The experiment has several dimensions of motion, including one parallel to the ground, so the motion of the ball does not directly test the force of gravity. They should not use it. The experiment has several dimensions of motion, including one parallel to the ground, so the motion of the ball does not directly test the force of gravity. They should use it. The experiment shows the ball falls toward the bottom of the hill, so it provides direct evidence that gravity pulls an object downward. They should use it. The experiment shows the ball falls toward the bottom of the hill, so it provides direct evidence that gravity pulls an object downward. They should not use it. Gravity should be tested in space, and this experiment could only be tested on Earth.
Physics
1 answer:
Ksenya-84 [330]2 years ago
8 0

The ball raised up the hill is given gravitational potential energy, which

causes it to roll spontaneously down the hill.

The statement that explains whether the ball rolling down the hill

experiment should be used is; <u>The experiment shows the ball falls toward </u>

<u>the bottom of the hill, so it provides direct evidence that gravity pulls an </u>

<u>object downward. They should use it.</u>

Reason:

The equation for the velocity of a ball falling down a hill is v = \sqrt{\dfrac{10}{7} \cdot g \cdot h}

Therefore, by increasing the height from which the ball rolls down the hill,

the velocity of the ball increases, which indicates that the ball is

accelerating, and therefore, being acted on by a force, the force of gravity.

Therefore;

Given that the ball falls or moves with increasing speed towards

the bottom of the hill, which shows that the motion is due to Earth's pull

known as the gravitational force, the experiment should be used.

Learn more here:

brainly.com/question/3175380

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A 1.60 m cylindrical rod of diameter 0.550 cm is connected to a power supply that maintains a constant potential difference of 1
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1.

Answer:

Part a)

\rho = 1.35 \times 10^{-5}

Part b)

\alpha = 1.12 \times 10^{-3}

Explanation:

Part a)

Length of the rod is 1.60 m

diameter = 0.550 cm

now if the current in the ammeter is given as

i = 18.7 A

V = 17.0 volts

now we will have

V = I R

17.0 = 18.7 R

R = 0.91 ohm

now we know that

R = \rho \frac{L}{A}

0.91 = \rho \frac{1.60}{\pi(0.275\times 10^{-2})^2}

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Part b)

Now at higher temperature we have

V = I R

17.0 = 17.3 R

R = 0.98 ohm

now we know that

R = \rho \frac{L}{A}

0.98 = \rho' \frac{1.60}{\pi(0.275\times 10^{-2})^2}

\rho' = 1.46 \times 10^{-5}

so we will have

\rho' = \rho(1 + \alpha \Delta T)

1.46 \times 10^{-5} = 1.35 \times 10^{-5}(1 + \alpha (92 - 20))

\alpha = 1.12 \times 10^{-3}

2.

Answer:

Part a)

i = 1.55 A

Part b)

v_d = 1.4 \times 10^{-4} m/s

Explanation:

Part a)

As we know that current density is defined as

j = \frac{i}{A}

now we have

i = jA

Now we have

j = 1.90 \times 10^6 A/m^2

A = \pi(\frac{1.02 \times 10^{-3}}{2})^2

so we will have

i = 1.55 A

Part b)

now we have

j = nev_d

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so we have

1.90 \times 10^6 = (8.5 \times 10^{28})(1.6 \times 10^{-19})v_d

v_d = 1.4 \times 10^{-4} m/s

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