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MissTica
2 years ago
8

Which statement explains whether or not a person should use an experiment of a ball rolling down a hill as evidence that the for

ce of gravity pulls objects straight down?(1 point) They should use it. Any experiment on Earth involving natural motion will provide direct evidence that gravity pulls objects straight down. They should use it. Any experiment on Earth involving natural motion will provide direct evidence that gravity pulls objects straight down. They should not use it. The experiment has several dimensions of motion, including one parallel to the ground, so the motion of the ball does not directly test the force of gravity. They should not use it. The experiment has several dimensions of motion, including one parallel to the ground, so the motion of the ball does not directly test the force of gravity. They should use it. The experiment shows the ball falls toward the bottom of the hill, so it provides direct evidence that gravity pulls an object downward. They should use it. The experiment shows the ball falls toward the bottom of the hill, so it provides direct evidence that gravity pulls an object downward. They should not use it. Gravity should be tested in space, and this experiment could only be tested on Earth.
Physics
1 answer:
Ksenya-84 [330]2 years ago
8 0

The ball raised up the hill is given gravitational potential energy, which

causes it to roll spontaneously down the hill.

The statement that explains whether the ball rolling down the hill

experiment should be used is; <u>The experiment shows the ball falls toward </u>

<u>the bottom of the hill, so it provides direct evidence that gravity pulls an </u>

<u>object downward. They should use it.</u>

Reason:

The equation for the velocity of a ball falling down a hill is v = \sqrt{\dfrac{10}{7} \cdot g \cdot h}

Therefore, by increasing the height from which the ball rolls down the hill,

the velocity of the ball increases, which indicates that the ball is

accelerating, and therefore, being acted on by a force, the force of gravity.

Therefore;

Given that the ball falls or moves with increasing speed towards

the bottom of the hill, which shows that the motion is due to Earth's pull

known as the gravitational force, the experiment should be used.

Learn more here:

brainly.com/question/3175380

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A high-jumper clears the bar and has a downward velocity of - 5.00 m/s just before landing on an air mattress and bouncing up at
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-- As she lands on the air mattress, her momentum is (m v)

Momentum = (60 kg) (5 m/s down) = 300 kg-m/s down

-- As she leaves it after the bounce,

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-- The impulse (change in momentum) is

Change = (60 kg-m/s up) - (300 kg-m/s down)

Magnitude of the change = <em>360 km-m/s </em>

The direction of the change is <em>up /\ </em>.

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3 years ago
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The answer for this question should be "false".
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Which force is greater the earth’s pull on the moon or the moon’s pull on the earth
Vitek1552 [10]

Answer:

The earth's pull on the moon

Explanation:

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3 years ago
If the distance between slits on a diffraction grating is 0.50 mm and one of the angles of diffraction is 0.25°, how large is th
Trava [24]

Answer:

-  path differnce = 2.18*10^-6

-  1538 lines

Explanation:

- The path difference for the waves that produce the pattern of diffraction, is given by the following formula:

path\ difference\ = dsin\theta           (1)

d: separation between slits = 0.50mm = 0.50*10^-3 m

θ: angle of a diffraction = 0.25°

Then, the path difference is:

path\ difference\ =(0.50*10^{-3}m)sin(0.25\°)=2.18*10^{-6}m

- The maximum number of bright lines are calculated by using the following formula:

m\lambda = dsin\theta           (2)

m: order of the bright

λ: wavelength = 650nm

The maximum bright is calculated for an angle of 90°:

m=\frac{(0.50*10^{-3}m)sin90\°}{650*10^{-9}m} \approx 769

The maxium number of bright lines are twice the previous result, that is, 1538 lines

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3 years ago
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fiasKO [112]

The distance of the rock from the base of the cliff is C) 20 m

Explanation:

The motion of the rock in this problem is a projectile motion, which consists of two independent motions:

- A uniform motion (constant velocity) along the horizontal direction

- An accelerated motion with constant acceleration (acceleration of gravity) in the vertical direction

We start by analyzing the vertical motion to find the time of flight of the rock (the time it takes to reach the ground). We can do it by using the suvat equation:

s=u_y t+\frac{1}{2}at^2

where, taking downward as positive direction,

s = 20 m is the vertical displacement of the rock

u_y=0 is the initial vertical velocity

t is the time of flight

a=g=9.8 m/s^2 is the acceleration of gravity

Solving for t,

t=\sqrt{\frac{2s}{g}}=\sqrt{\frac{2(20)}{9.8}}=2.02 s

Now we can analzye the horizontal motion: the rock moves horizontally with a constant velocity of

v_x = 10 m/s

Therefore, the horizontal distance covered after a time t is

d=v_x t

and substituting t = 2.02 s, we find the final distance of the rock from the base of the cliff:

d=(10)(2.02)=20 m

Learn more about projectile motion:

brainly.com/question/8751410

#LearnwithBrainly

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