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MissTica
2 years ago
8

Which statement explains whether or not a person should use an experiment of a ball rolling down a hill as evidence that the for

ce of gravity pulls objects straight down?(1 point) They should use it. Any experiment on Earth involving natural motion will provide direct evidence that gravity pulls objects straight down. They should use it. Any experiment on Earth involving natural motion will provide direct evidence that gravity pulls objects straight down. They should not use it. The experiment has several dimensions of motion, including one parallel to the ground, so the motion of the ball does not directly test the force of gravity. They should not use it. The experiment has several dimensions of motion, including one parallel to the ground, so the motion of the ball does not directly test the force of gravity. They should use it. The experiment shows the ball falls toward the bottom of the hill, so it provides direct evidence that gravity pulls an object downward. They should use it. The experiment shows the ball falls toward the bottom of the hill, so it provides direct evidence that gravity pulls an object downward. They should not use it. Gravity should be tested in space, and this experiment could only be tested on Earth.
Physics
1 answer:
Ksenya-84 [330]2 years ago
8 0

The ball raised up the hill is given gravitational potential energy, which

causes it to roll spontaneously down the hill.

The statement that explains whether the ball rolling down the hill

experiment should be used is; <u>The experiment shows the ball falls toward </u>

<u>the bottom of the hill, so it provides direct evidence that gravity pulls an </u>

<u>object downward. They should use it.</u>

Reason:

The equation for the velocity of a ball falling down a hill is v = \sqrt{\dfrac{10}{7} \cdot g \cdot h}

Therefore, by increasing the height from which the ball rolls down the hill,

the velocity of the ball increases, which indicates that the ball is

accelerating, and therefore, being acted on by a force, the force of gravity.

Therefore;

Given that the ball falls or moves with increasing speed towards

the bottom of the hill, which shows that the motion is due to Earth's pull

known as the gravitational force, the experiment should be used.

Learn more here:

brainly.com/question/3175380

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A car traveling at 5m/s starts to speed up after 3 seconds its velocity has increased to 11 m/s what is its acceleration
vfiekz [6]

Answer:

a=(v-u)/t

Explanation:

a =(11-5)/3

a= 8/3

a= 2.6 m/s

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A Honda Civic travels in a straight line along a road. Its distance x from a stop sign is given as a function of time t by the e
andrew-mc [135]
Average velocity = (x( 2.08 ) - x ( 0 )) / ( 2.08 s - 0 s )
x ( 2.08 ) = 1.42 * 2.08² - 0.05 * 2.08³ =
= 1.42 * 4.3264 - 0.443456 = 6.143484 - 0.443456 ≈ 5.7 m
v = ( 5.7 m - 0 m) / (2.08 s - 0 s ) = 5.7 / 2.08 m/s = 27.4 m/s
3 0
3 years ago
What are the conditions of the thermonuclear fusion reaction in the sun?​
Verizon [17]

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8 0
2 years ago
Explain why frog will not look green under the red light?
IrinaVladis [17]
A frog can be many different colours. It appears green under normal 'white' light because it absorbs all the other colours in the light's spectrum apart from green. It reflects the green light back and that is picked up by your eye.

If the light is red, there is no green in the spectrum of the light, only red. So, the red light will be absorbed and there is no green to be reflected back for you to see. Therefore, the frog will not look green.
8 0
3 years ago
Um objeto de 4cm de altura está a 30cm de um espelho côncavo, cujo raio de curvatura tem valor absoluto de 20cm.
Shkiper50 [21]

a) The distance of the image from the mirror is 15 cm

b) The size of the image is -2 cm (inverted)

Explanation:

a)

We can solve this first part of the problem by applying the mirror equation:

\frac{1}{f}=\frac{1}{p}+\frac{1}{q}

where

f is the focal length

p is the distance of the object from the mirror

q is the distance of the image from the mirror

For a mirror, the focal length is half the radius of curvature, R:

f=\frac{R}{2}

For this mirror, R = 20 cm, so its focal length is

f=\frac{20}{2}=+10 cm (positive for a concave mirror)

Here we also know:

p = 30 cm is the distance of the object from the mirror

So, by applying the equation, we can find q:

\frac{1}{q}=\frac{1}{f}-\frac{1}{p}=\frac{1}{10}-\frac{1}{30}=\frac{1}{15} \rightarrow q = 15 cm

b)

We can solve this part by using the magnification equation:

M=-\frac{y'}{y}=\frac{q}{p}

where

y' is the size of the image

y is the size of the object

q is the distance of the image from the mirror

p is the distance of the object from the mirror

Here we have:

q = 15 cm

p = 30 cm

y = 4 cm

Solving for y', we find the size of the image:

y'=-y\frac{q}{p}=-(4)\frac{15}{30}=-2 cm

and the negative sign means that the image is inverted.

#LearnwithBrainly

6 0
3 years ago
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