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Art [367]
3 years ago
8

A 2-kg object is moving horizontally across a frictionless surface with a speed of 4 m/s. How much force is required to keep the

object moving at this speed and in this direction?​
Physics
1 answer:
FinnZ [79.3K]3 years ago
8 0

Answer:

  none

Explanation:

Newton's first law says an object in motion will stay in motion at the same speed and direction unless acted upon by some force.

No force is necessary for the object to keep its speed and direction on a frictionless surface.

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Name two ways that friction is harmful and two ways that friction is helpful to you when riding a bicycle
lawyer [7]
<u>Harmful</u><u />

-causes heat; if it's not used correctly, it can cause injury
-when falling, the friction between your knee/leg and the ground can cause scrapes
<u>
</u>
<u>Helpful</u><u />

-helps stop the bike, the brakes rub against the tire which slows it down to a stop
-it can also help move the bike; the chains rub against tires which accelerate the bike
6 0
3 years ago
The speed of sound is measured to be 340 m/s on a certain day.
ziro4ka [17]
Answer: 1,224 km/h

Explanation:

To do this, we pick the first unit and convert
Picking m first and converting to km:
Since we're converting from a non-prefix to a prefix, we divide the value by the prefix were taking it to. In this case, kilo = 10³ which means we're going to divide our value by 1000 to convert it from m to km
340 m/s ÷ 1000 = 0.34 km/s
Now, let's convert our seconds to hour:
We'll need to calculate how many hours is equivalent to one second first;
1 hr = 60×60 seconds
X hr = 1 second
*Cross multiply*
1 × 1 = X × 60 × 60
1 = 3,600 X
X = 1 / 3,600
X = 2.778×10⁻⁴ hour
So, in the place of "1 Second", we're going to be inserting 2.778×10⁻⁴ hour instead
0.34 km / s = 0.34 km / 2.778×10⁻⁴ hour
(0.34 / 2.778×10⁻⁴) km/hour
1,224 km/h.
340 m/s = 1,224 km/h
6 0
2 years ago
Any help????????????
pashok25 [27]
The answer should be D
3 0
3 years ago
Read 2 more answers
A set of four capacitors are attached to a 12V battery in the circuit shown below. All capacitances are measured in milli-Farads
Bond [772]

The amount of electric charge that resides on each capacitor once it is fully charged is 0.37 C.

<h3>Total capacitance of the circuit</h3>

The total capacitance of the circuit is calculated as follows;

Capacitors in series;

1/Ct = 1/8 + 1/7.5

1/Ct = 0.25833

Ct = 3.87 mF

Capacitors is parallel;

Ct = 3.87 mF + 12 mF + 15 mF

Ct = 30.87 mF

Ct = 0.03087 F

<h3>Charge in each capacitor</h3>

Q = CV

Q = 0.03087 x 12

Q = 0.37 C

Thus, the amount of electric charge that resides on each capacitor once it is fully charged is 0.37 C.

Learn more about capacitors here:  brainly.com/question/13578522

#SPJ1

3 0
2 years ago
Which best describes the electromagnetic force?
Solnce55 [7]
B.strong but weaker than the weak force
7 0
3 years ago
Read 2 more answers
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