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fenix001 [56]
3 years ago
13

water flows in a pipe of a terminal of A1=0.02 m2 with a speed of V1=2 m/s. At the second end of the pipe A2=0.04 m2, the speed

of flow is V2=_______m/s
Physics
1 answer:
weeeeeb [17]3 years ago
8 0
A1*V1=A2*V2
0.02*2=0.04*V2
V2=1 m/s
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Explanation:

The momentum of the three objects are as follow :

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Before collision, the momentum of the system is :

P_i=11+(-65)+(-100)\\\\P_i=-154\ kg-m/s

After collison, they move together. It means it is a case of inelastic collision. In this type of collision, the momentum of the system remains conserved.

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Answer:

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Explanation:

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KE = 1/2(75)(6.5)²

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2 years ago
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Explanation:

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