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Furkat [3]
3 years ago
6

a new car is advertised as having anti-noise technology. The manufacturer claims that inside the car any sound on negated. Evalu

ate the possibility of such a claim. What would have to be created to cause destructive interference with any sound in the car? Do you believe the manufacturers claim is correct?
Physics
1 answer:
nirvana33 [79]3 years ago
5 0

Answer:

I guess you mean that any sound coming from outside is negated, first, this would mean that you can not hear some signals that may help you to avoid accidents, so you do not want this technology.

Now, let's see if it is possible.

Suppose you have a soundwave approaching the car, the car needs to cancel the soundwaves as the soundwaves approach to the surface, to do it, you need to create another wave that is equal in amplitude, but with a change of phase of pi.

in order to do this, the car must be able to "analyze" the coming soundwave and instantly create another one to cancel it. Suppose that the sound is canceled. now if the sound changes, the car must be able to also change the sound that the car is producing, this instantaneous change is one of the problems.

Another problem is that, as you know, the sound propagates as spherical waves, this means that the wavefront of a wave produced far away will have a bigger radius than the soundwave produced by the car, then we never will have a situation where the wavefront is canceled: This means that we only can cancellate the sound in some areas of the car, and we still will have some sound in other parts of the car.

Another way to isolate the car is with isolating panels, those panels absorb the sound and transmit a very little amount of it (those panels are used in recording studios, for example). With enough of those you can cancel almost all the sound coming from the outside, but to do this you will need a big car because the amount of isolating material needed is a lot.  

We can conclude that the manufacturers claim is not correct.

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3 years ago
A sled of mass m is being pulled horizontally by a constant horizontal force of magnitude F. The coefficient of kinetic friction
steposvetlana [31]

Answer:

The average velocity of the sled is vavg = s/t.

Explanation:

Hi there!

The average velocity is calculated as the traveled distance over time:

vavg = Δx/Δt

Where:

vavg = average velocity.

Δx = traveled distance.

Δt = elapsed time.

We already know the traveled distance (s) and also know the time it takes the sled to travel that distance (t). Then, the average velocity can be calculated as follows:

vavg = s/t

Have a nice day!

6 0
3 years ago
1. What affects a material's resistance?
Ghella [55]

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3 0
3 years ago
A pulley system has an MA of 4. How much force would be necessary to pull a 200 newton box
Airida [17]

Mechanical advantage is defined as

MA = \frac{F_{output}}{F_{input}}

MA = 4

now we will have

F_{output} = 200 N

as we need to pull up a box of weight 200 N

now by above formula we can find how much force it requires to pull up the box

4 = \frac{F_{output}}{F_{input}}

4 = \frac{200}{F_{input}}

F_{input} = \frac{200}{4} = 50 N

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Answer:

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Explanation:

\lambda = Wavelength of the light absorbed = 91.65 nm = 91.65 x 10⁻⁹ m

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n_{1} = 1

Using conservation of energy

\frac{hc}{\lambda} = (13.6\times1.6\times10^{-19}) (\frac{1}{n_{1}^2} - \frac{1}{n_{2}^2} )\\\frac{(6.63\times10^{-34})(3\times10^{8})}{(91.65\times10^{-9})} = (13.6\times1.6\times10^{-19}) (\frac{1}{1^2} - \frac{1}{n^2} )\\2.17\times10^{-18} = (21.76\times10^{-19}) (\frac{1}{1^2} - \frac{1}{n^2} )\\n = 19

4 0
3 years ago
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