Answer:
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Explanation:
<u>Answer:</u> Maximum work that can be obtained by given amount of methanol is -343kJ.
<u>Explanation:</u>
For the given chemical reaction:
By Stoichiometry of the reaction:
2 moles of methanol does a work of 1372 kJ.
So, 0.5 moles of methanol will do a work of = 
Hence, maximum work that can be obtained by given amount of methanol is -343kJ.
D. Making the reactant particles larger
To calculate the new pressure, we can use Boyle’s law to relate these two scenarios (Boyle’s law is used because the temperature is assumed to remain constant). Boyle’s law is:
P1V1 = P2V2,
Where “P” is pressure and “V” is volume. The pressure and volume of the first scenario is 215 torr and 51 mL, respectively, and the second scenario has a volume of 18.5 L (18,500 mL) and the unknown pressure - let’s call that “x”. Plugging these into the equation:
(215 torr)(51 mL) =(“x” torr)(18,500 mL)
x = 0.593 torr
The final pressure exerted by the gas would be 0.593 torr.
Hope this helps!
