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Korvikt [17]
10 months ago
12

An individual is hospitalized and the initial blood work indicates high levels of hco3- in the blood and a ph of 7. 47. This wou

ld indicate the individual probably has?
Chemistry
1 answer:
expeople1 [14]10 months ago
5 0

An individual is hospitalized and the initial blood work indicates high levels of HCO_{3} ^{-} in the blood and a pH of 7. 47. This would indicate the individual probably has compensated respiratory acidosis.

A chronic illness usually leads to compensated respiratory acidosis because the kidneys have time to adjust to the delayed onset. Even if the PCO_{2} is elevated in a compensated respiratory acidosis, the pH is within the usual range.

The kidneys counteract a respiratory acidosis by increasing the amount of HCO_{3} that tubular cells reabsorb from the tubular fluid, the amount of H^{+} that collecting duct cells secrete while also producing HCO_{3} , and the amount of NH_{3} buffer that is formed through ammoniagenesis.

Respiratory acidosis is frequently brought on by hypoventilation as a result of: breathing depression , paralysis of the respiratory muscles, diseases of the chest wall , abnormalities of the lung parenchyma and abdominal squeezing.

Learn more about Respiratory acidosis here;

brainly.com/question/9694207

#SPJ4

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nikitadnepr [17]

Answer:

a)\ 2FeSO4 \xrightarrow{\text{Heat}} SO_3+SO_2+Fe_2O_3\\b)\ Decomposition\ Reaction

Explanation:

<em>Ferrous Sulphate</em>(FeSO4)<em> is generally found as Lime-Green Crystals. On heating, these crystals almost immediately turn white-yellow. They then, break down to produce an anhydrous mixture of Sulphur Trioxide </em>(SO_3)<em>, Sulphur Dioxide </em>(SO_2)<em>  as well as Ferric Oxide </em>(Fe_2O_3)<em>.</em>

<em>We can hence, frame a skeletal equation of this reaction and try to balance it.</em>

<em>Hence,</em>

FeSO4 \xrightarrow{\text{Heat}} SO_3+SO_2+Fe_2O_3

<em>Now,</em>

<em>a)In order to balance it through the 'Hit &Trial Method', we'll follow a series of </em><em>steps</em><em>:</em>

<em>1. First, lets compare the number of  Fe (Iron) atoms on the RHS and LHS. We find that, the no. of Fe Atoms on the RHS is twice the number of Fe Atoms on the LHS. We hence, add a co-effecient 2 beside </em>FeSO_4.

<em>2. Now, Iron atoms, Sulphur Atoms and Oxygen atoms occur 2, 2, 8 respectively on both the sides:</em>

<em> Hence, As all the other elements as well as iron, balance, we've arrived upon our Balanced Equation :</em>

<em> </em>2FeSO4 \xrightarrow{\text{Heat}} SO_3+SO_2+Fe_2O_3

<em>b) We know that, decomposition reactions are [generally] endothermic reactions in which Large Compounds </em><em>decompose </em><em>into smaller elements and compounds. Here, as Ferrous Sulphate </em><em>decomposes </em><em>into Sulphur Dioxide, Sulphur Trioxide and Ferric Oxide, the reaction that occurs here is </em><em>Decomposition Reaction.</em>

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2 years ago
Why are hydrogen bonds so essential to the structure of dna?
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3 years ago
1.A telescope is a tool that helps people observe distant objects. In the simplest telescope design, incoming light hits a lens
Dahasolnce [82]

Answer:

it is refraction

Explanation:

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3 years ago
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3 years ago
Calculate the molarity of a solution<br> made by 1,5kg of K. CO₂ in 850 mL<br> of water.
anastassius [24]

Answer:

17.83M

Explanation:

Given parameters:

Mass of KCO₂ = 1.5kg

Volume of water  = 850mL

Unknown:

Molarity of solution  = ?

Solution:

Molarity is defined as the number of moles per unit volume. It is the number of moles of solute in a given volume of solution.

   Molarity  = \frac{number of moles }{volume}

Number of moles of solute  = \frac{mass of KCO_{2} }{molar mass}

  Molar mass of KCO₂  = 39 + 12 + 3(16) = 99g/mol

  Number of moles  = \frac{1500}{99}   = 15.15moles

   850mL : gives 0.85L

     

Molarity  = \frac{15.15}{0.85}   = 17.83M

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3 years ago
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