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Korvikt [17]
1 year ago
12

An individual is hospitalized and the initial blood work indicates high levels of hco3- in the blood and a ph of 7. 47. This wou

ld indicate the individual probably has?
Chemistry
1 answer:
expeople1 [14]1 year ago
5 0

An individual is hospitalized and the initial blood work indicates high levels of HCO_{3} ^{-} in the blood and a pH of 7. 47. This would indicate the individual probably has compensated respiratory acidosis.

A chronic illness usually leads to compensated respiratory acidosis because the kidneys have time to adjust to the delayed onset. Even if the PCO_{2} is elevated in a compensated respiratory acidosis, the pH is within the usual range.

The kidneys counteract a respiratory acidosis by increasing the amount of HCO_{3} that tubular cells reabsorb from the tubular fluid, the amount of H^{+} that collecting duct cells secrete while also producing HCO_{3} , and the amount of NH_{3} buffer that is formed through ammoniagenesis.

Respiratory acidosis is frequently brought on by hypoventilation as a result of: breathing depression , paralysis of the respiratory muscles, diseases of the chest wall , abnormalities of the lung parenchyma and abdominal squeezing.

Learn more about Respiratory acidosis here;

brainly.com/question/9694207

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Answer:

\fbox{0.3125 M}

Given:

  • Given mass of NaOH = 30 gram
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To find:

Molarity = ?

Solution:

<em>Molarity is nothing but the number of moles of solute dissolved in per litre of solution. given by </em><em>formula,</em>

Molarity =  \frac{given  \: mass}{molar \: mass  \times Volume}

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2 years ago
A solution has a pOH of 8.7 so what is the pH of the solution? Is the solution acidic, basic, or neutral?
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pH = 14 - pOH

pH = 14 - 8.7

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What volume of a 6.0m hcl solution is required to make 250.0 milliters of 1.5 m hcl
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Answer : The volume for 6.0m HCl solution required = 62.5 ml

Solution : Given,

Initial concentration of HCl solution = 6.0m

Final concentration of HCl solution = 1.5m

Final volume of HCl solution = 250 ml

Initial volume of HCl solution = ?

Formula used for dilution is,

M_1V_1=M_2V_2

where,

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M_2 = final concentration

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Now put all the given values in above formula, we get the initial volume of HCl solution.

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Therefore, the volume for 6.0m HCl solution required = 62.5 ml


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4 years ago
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