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Oduvanchick [21]
3 years ago
6

Please help me with the questions?

Chemistry
1 answer:
weqwewe [10]3 years ago
6 0

Answer:

1. Forecast

2. Cold front

3. Shelf Cloud

4. Barometer

5. Pressure

6 Prevailing Westerlies

7. Thermometer

8. Weather

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a) Diamond and graphite are two different forms of pure elemental carbon with densities of 3.51 g/cc and 2.25 g/cc respectively.
dybincka [34]
Density can be calculated using the following rule:
density = mass / volume
Therefore,
volume = mass / density

For diamond:
we have mass = 0.5 grams and density = 3.51 g / cm^3
Substituting in the rule, we can calculate the volume of diamond as follows:
volume = 0.5 / 3.51 = 0.14245 cm^3

For graphite:
we have mass = 0.5 grams and density = 2.25 g / cm^3
Substituting in the rule, we can calculate the volume of graphite as follows:
volume = 0.5 / 2.25 = 0.2223 cm^3
8 0
3 years ago
When milk of magnesia reacts with the acids in your stomach which type of reaction has taken place?
uysha [10]

Neutralization reaction

5 0
3 years ago
Read 2 more answers
Copper has two isotopes. Copper-63, which has an atomic mass of of 62.93 u and copper-65, which has an atomic mass of 64.93 u. I
Svetach [21]

Answer:

for more details are in the pic

3 0
3 years ago
Carbon disulfide is prepared by heating sulfur and charcoal. The chemical equation is S2(g)+C(s)↽−−⇀CS2(g)????c=9.40 at 900 K Ho
Maru [420]

Answer : The mass of CS_2 is, 555.028 grams

Explanation :

First er have to calculate the concentration of S_2.

\text{Concentration of }S_2=\frac{\text{Moles of }S_2}{\text{Volume of solution}}=\frac{8.08mole}{5.35L}=1.51mole/L

Now we have to calculate the concentration of CS_2.

The given balanced chemical reaction is,

                          S_2(g)+C(s)\rightleftharpoons CS_2(g)

Initial conc.         1.51       0         0

At eqm. conc.   (1.51-x)  (x)       (x)

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[CS_2]}{[S_2]}

Now put all the given values in this expression, we get :

9.40=\frac{x}{(1.51-x)}

By solving the term 'x', we get :

x = 1.365 M

Concentration of CS_2 = x M = 1.365 M

Now we have to calculate the moles of CS_2.

\text{Moles of }CS_2=\text{Concentration of }CS_2}\times \text{Volume of solution}=1.365mole/L\times 5.35L=7.303mole

Now we have to calculate the mass of CS_2.

Molar mass of CS_2 = 76 g/mole

\text{Mass of }CS_2=\text{Moles of }CS_2}\times \text{molar mass of }CS_2}=7.303mole\times 76g/mole=555.028g

Therefore, the mass of CS_2 is, 555.028 grams

3 0
4 years ago
**EASY**
Svetach [21]
Answer: But because part 2 stays the same
3 0
3 years ago
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