Answer:
It basically messes up the results
Explanation:
Pen ink consists of resins, pigments and other colouring dyes dissolved in appropriate solvents like propylene glycol, propyl alcohol and some other ethers. If the ball point pen is used to mark on the chromatography paper then these pigments will also move along with the solvent and interfere with the spots of our analyte.
If you use a ball point pen when doing a chromatogram, then the ink would separate as it is a mixture and run down the paper.
Graphite, or pencil lead however, is not an organic material and therefore will not be affected by common organic solvents used for thin-layer chromatography. Pen ink on the other hand will be readily absorbed by the solvent and will move up the plate.
There are 2 moles of O stones present in 88 grams of CO2. Why? Well, we can find the amount of moles present in 88 grams of CO2 by dividing the mass by the molar mass. The mass of CO2 comes out to be 88 grams. The molar mass of CO2 comes out to be 44 grams. Because 88 is the mass of CO2 and 44 is the molar mass of CO2, we can divide 88 by 44 to identify that there are 2.0 moles of O atoms present in 88 grams of CO2.
Your final answer: There are 2.0 moles of O atoms present in 88 grams of CO2. Your final answer to this question is D, or 2.0 moles. If you need to better understand, let me know and I will gladly assist you.
Answer:
449.5 g
Explanation:
Silver sulfate- Ag2SO4
M(Ag)=107 g/mol => M(Ag2)=214 g/mol
M(S)=32 g/mol
M(O)=16 g/mol => M(O4)=64 g/mol
M(Ag2SO4)=310 g/mol
n=1.45 mol
m(Ag2SO4)=M(Ag2SO4)*n=310 g/mol *1.45 mol= 449.5 g
