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3 years ago

What are the zeros of the quadratic function in the graph?

Mathematics

2 answers:

blagie [28]3 years ago

6 0

Answer:

Step-by-step explanation:

1. Define word "zeros"

zeros = x-intercepts

2. Find x-intercepts

(-2, 0) and (-4, 0)

x-intercepts = -2, -4 or -4, -2

ser-zykov [4K]3 years ago

6 0

Answer:

C) (-4,-2)

Step-by-step explanation:

The zeroes is where the function passes through 0, and in this graph it passes through (0,-4) and (0,-2)

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In a statistics class, 10 scores were randomly selected with the following results (mean = 71.5): 74, 73, 77, 77, 71, 68, 65, 77

algol13

Answer:

Range: 12

Step-by-step explanation:

65, 66, 67, 68, 71, 73, 74, 77, 77, 77

Formula:

Range: highest value - lowest value = final answer

Range: 77 - 65 = 12

3 0

3 years ago

What is the difference between 5 hundreds and 3 tens?

Umnica [9.8K]

Answer:

5 tens and 3 hundreds = 50 + 300 = 350. That is basically asking what number goes 5-3-2. This is because 5 hundreds means 5 in the hundreds place, or 500. 3 tens is just saying 3 in the tens place, or 30.

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Activity 4: Performance Task

Nookie1986 [14]

An arithmetic progression is simply a progression with a common difference among consecutive terms.

The sum of multiplies of 6 between 8 and 70 is 390
The sum of multiplies of 5 between 12 and 92 is 840
The sum of multiplies of 3 between 1 and 50 is 408
The sum of multiplies of 11 between 10 and 122 is 726
The sum of multiplies of 9 between 25 and 100 is 567
The sum of the first 20 terms is 630
The sum of the first 15 terms is 480
The sum of the first 32 terms is 3136
The sum of the first 27 terms is -486
The sum of the first 51 terms is 2193

(a) Sum of multiples of 6, between 8 and 70

There are 10 multiples of 6 between 8 and 70, and the first of them is 12.

This means that:

$\mathbf{a = 12}$

$\mathbf{n = 10}$

$\mathbf{d = 6}$

The sum of n terms of an AP is:

$\mathbf{S_n = \frac n2(2a + (n - 1)d)}$

Substitute known values

$\mathbf{S_{10} = \frac{10}2(2*12 + (10 - 1)6)}$

$\mathbf{S_{10} = 390}$

(b) Multiples of 5 between 12 and 92

There are 16 multiples of 5 between 12 and 92, and the first of them is 15.

This means that:

$\mathbf{a = 15}$

$\mathbf{n = 16}$

$\mathbf{d = 5}$

The sum of n terms of an AP is:

$\mathbf{S_n = \frac n2(2a + (n - 1)d)}$

Substitute known values

$\mathbf{S_{16} = \frac{16}2(2*15 + (16 - 1)5)}$

$\mathbf{S_{16} = 840}$

(c) Multiples of 3 between 1 and 50

There are 16 multiples of 3 between 1 and 50, and the first of them is 3.

This means that:

$\mathbf{a = 3}$

$\mathbf{n = 16}$

$\mathbf{d = 3}$

The sum of n terms of an AP is:

$\mathbf{S_n = \frac n2(2a + (n - 1)d)}$

Substitute known values

$\mathbf{S_{16} = \frac{16}2(2*3 + (16 - 1)3)}$

$\mathbf{S_{16} = 408}$

(d) Multiples of 11 between 10 and 122

There are 11 multiples of 11 between 10 and 122, and the first of them is 11.

This means that:

$\mathbf{a = 11}$

$\mathbf{n = 11}$

$\mathbf{d = 11}$

The sum of n terms of an AP is:

$\mathbf{S_n = \frac n2(2a + (n - 1)d)}$

Substitute known values

$\mathbf{S_{16} = \frac{11}2(2*11 + (11 - 1)11)}$

$\mathbf{S_{11} = 726}$

(e) Multiples of 9 between 25 and 100

There are 9 multiples of 9 between 25 and 100, and the first of them is 27.

This means that:

$\mathbf{a = 27}$

$\mathbf{n = 9}$

$\mathbf{d = 9}$

The sum of n terms of an AP is:

$\mathbf{S_n = \frac n2(2a + (n - 1)d)}$

Substitute known values

$\mathbf{S_{9} = \frac{9}2(2*27 + (9 - 1)9)}$

$\mathbf{S_{9} = 567}$

(f) Sum of first 20 terms

The given parameters are:

$\mathbf{a = 3}$

$\mathbf{d = 3}$

$\mathbf{n = 20}$

The sum of n terms of an AP is:

$\mathbf{S_n = \frac n2(2a + (n - 1)d)}$

Substitute known values

$\mathbf{S_{20} = \frac{20}2(2*3 + (20 - 1)3)}$

$\mathbf{S_{20} = 630}$

(f) Sum of first 15 terms

The given parameters are:

$\mathbf{a = 4}$

$\mathbf{d = 4}$

$\mathbf{n = 15}$

The sum of n terms of an AP is:

$\mathbf{S_n = \frac n2(2a + (n - 1)d)}$

Substitute known values

$\mathbf{S_{15} = \frac{15}2(2*4 + (15 - 1)4)}$

$\mathbf{S_{15} = 480}$

(g) Sum of first 32 terms

The given parameters are:

$\mathbf{a = 5}$

$\mathbf{d = 6}$

$\mathbf{n = 32}$

The sum of n terms of an AP is:

$\mathbf{S_n = \frac n2(2a + (n - 1)d)}$

Substitute known values

$\mathbf{S_{32} = \frac{32}2(2*5 + (32 - 1)6)}$

$\mathbf{S_{32} = 3136}$

(g) Sum of first 27 terms

The given parameters are:

$\mathbf{a = 8}$

$\mathbf{d = -2}$

$\mathbf{n = 27}$

The sum of n terms of an AP is:

$\mathbf{S_n = \frac n2(2a + (n - 1)d)}$

Substitute known values

$\mathbf{S_{27} = \frac{27}2(2*8 + (27 - 1)*-2)}$

$\mathbf{S_{27} = -486}$

(h) Sum of first 51 terms

The given parameters are:

$\mathbf{a = -7}$

$\mathbf{d = 2}$

$\mathbf{n = 51}$

The sum of n terms of an AP is:

$\mathbf{S_n = \frac n2(2a + (n - 1)d)}$

Substitute known values

$\mathbf{S_{51} = \frac{51}2(2*-7 + (51 - 1)*2)}$

$\mathbf{S_{51} = 2193}$

Read more about arithmetic progressions at:

brainly.com/question/13989292

4 0

2 years ago

Read 2 more answers

A newspaper’s cover page is 3/8 text, and photographs fill the rest. If 2/5 of the text is an article about endangered species,

jolli1 [7]

Answer:

$\frac{3}{20}$

Step-by-step explanation:

Let x be the cover page

We are given that a newspaper 's cover page is $\frac{3}{8}$ text and photograph fill the rest.

We have to find that how much part of cover's page is the article about endangered species

Text = $\frac{3}{8}x$

Remaining part = $x-\frac{3}{8} x$

Remaining part = $\frac{8x-3x}{8}=\frac{5}{8} x$

Therefore, a newspaper;s cover page fill with Photograph = $\frac{5}{8}$

If the article about endangered species= $\frac{2}{5}$ of text

Therefore, the article about endangered species= $\frac{2}{5}\times\frac{3x}{8}=\frac{3}{20}x$

Hence, the article about endangered species is $\frac{3}{20}$ of the cover page.

7 0

3 years ago

Read 2 more answers

What happens when x is a very small negative number?

marshall27 [118]

With this line, we see that when x is a small negative number, F(x) is a very large negative number, or B.

Remember that F(x) is the same as y. And looking at the pattern of the line, the greater the negative x is, the smaller the negative y is.

3 0

3 years ago