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ladessa [460]
3 years ago
5

A 3.0 kg object moving 8.0 m/s in the positive x-direction has a one-dimensional elastic collision with an object of mass, M, in

itially at rest. After the collision the object of unknown mass has a velocity of 6.0 m/s in the positive x direction. What is M
Physics
1 answer:
finlep [7]3 years ago
8 0

Answer:

<h3>1kg</h3>

Explanation:

According to law of conservation of momentum

m1u1+ m2u2 = (m1+m2)v

m1 and m2 are the masses of the object

u1 and u2 are their initial velocities

v is their common velocity

Given

m1 = 3kg

m2 = M

u1 = 8m/s

u2 = 0m/s (object at rest)

v = 6.0m/s

Substitute and get M

3(8) + M(0) = (3+M)6

24 = 18+6M

24-18 = 6M

6 = 6M

M = 1kg

Hence the mass M is 1kg

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If you were to walk with a speed if 2m/s for 2 hours how far would you travel
olga nikolaevna [1]
So simply it to 120m/m for 120 minutes. So then you multiply 120x120 and that equals 14,400
7 0
2 years ago
A conical container of radius 6 ft and height 18 ft is filled to a height of 11 ft of a liquid weighing 64.4 lb divided by ft cu
prisoha [69]

Answer:

Hello there, please see explanations for step by step answer.

Explanation:

Radius 6 ft and

Height 18 ft is filled to a height of 11 ft of a liquid weighing 64.4 lb divided by ft cubedlb/ft3.

How much work will it take to pump the contents to the​ rim.

See attached documents for clear solvings and further step by step explanations

4 0
3 years ago
How much work do you do on a 15 N book in lifting it straight up for a distance of<br> 0.40 meters?
astra-53 [7]

Answer:

Work done, W = 6 J

Explanation:

It is given that,

Force of gravity acting on the book, weight of the book is 15 N

We need to find the work done in lifting the book straight up for a distance of  0.4 meters.

The weight of the book is acting in downward direction and the book is lifted straight up, it means angle between them is 180 degrees. Work done is given by :

W=Fd\cos180\\\\W=15\times 0.4\times \cos180\\\\W=-6\ J

So, the magnitude of work done in lifting the book is 6 joules.

7 0
3 years ago
Please help
Hitman42 [59]

Answer:

3200 m/s

Explanation:

The speed of Sound through Argon is 319.

The speed of sound in any chemical element in the fluid phase has one temperature-dependent value. In the solid phase, different types of sound wave may be propagated, each with its own speed: among these types of wave are longitudinal (as in fluids), transversal, and (along a surface or plate) extensional.

If argon could exist as solid, then 3200 m/s is the best speed.

7 0
3 years ago
Read 2 more answers
Now the elevator is moving downward with a velocity of v = -2.8 m/s but accelerating upward with an acceleration of a = 5.5 m/s2
borishaifa [10]

Answer:

160.75 N

Explanation:

The downward velocity has no effect on the force situation, it is only changes in velocity (plus, of course, gravity, which is always there) that require a force. At constant velocity, the bottom spring s_3 is supporting its mass m_3 to balance gravity.

As the elevator slows, though, it also ends up slowing down the spring arrangement, too. However, because the stretching takes time, it means that some damped harmonic motion will be set up in the spring chain.

When the motion has finally damped out, the net force the bottom spring s3 exerts on m3 has two components--that of gravity and of the deceleration of the elevator:

F_3net = m3 * (g + a) = 10.5×(9.81+5.5)= 10.5×15.31= 160.75 N

5 0
3 years ago
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