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ladessa [460]
3 years ago
5

A 3.0 kg object moving 8.0 m/s in the positive x-direction has a one-dimensional elastic collision with an object of mass, M, in

itially at rest. After the collision the object of unknown mass has a velocity of 6.0 m/s in the positive x direction. What is M
Physics
1 answer:
finlep [7]3 years ago
8 0

Answer:

<h3>1kg</h3>

Explanation:

According to law of conservation of momentum

m1u1+ m2u2 = (m1+m2)v

m1 and m2 are the masses of the object

u1 and u2 are their initial velocities

v is their common velocity

Given

m1 = 3kg

m2 = M

u1 = 8m/s

u2 = 0m/s (object at rest)

v = 6.0m/s

Substitute and get M

3(8) + M(0) = (3+M)6

24 = 18+6M

24-18 = 6M

6 = 6M

M = 1kg

Hence the mass M is 1kg

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Which group of measurements is the most precise? A) 2 g, 3 g, 4 g B) 2 g, 2.5 g, 3 g C) 2.0 g, 3.0 g, 4.0 g, 5.0 g D) 2.0 g, 3.0
siniylev [52]
The answer to your question is A
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3 years ago
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svlad2 [7]

The correct answer is  1.4285714.

In physics, velocity is characterised as a vector measurement of the motion's direction and speed. To be more precise, the rate of change in an object's position relative to a frame of reference and time is another way to describe velocity. The definition of velocity simply states the rate of motion of an object in a specific direction. It determines how quickly or slowly something is going.

Velocity = distance/ time  

Thus time = distance/velocity

Here velocity = 350m/s

diatnce = 500 m

time = 500/350

time = 1.42857142857

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1 year ago
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Katarina [22]

Answer:

0.5x35=17.5

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4 0
3 years ago
A rock is suspended by a light string. When the rock is in air, the tension in the string is 43.8 N . When the rock is totally i
sergeinik [125]

Answer:

Density of unknown liquid is 2047 kg/m^3

Explanation:

When rock is suspended in air then the weight of the rock is counter balanced by the tension force in the string

So here we have

T = mg = 43.8 N

now when the rock is immersed in water then the tension in the string is and buoyancy force due to water is counter balanced by the weight of the object

so here we have

T_1 + F_b = mg

31.3 + F_b = 43.8

F_b = 43.8 - 31.3 = 12.5 N

now we have

(1000)V(9.81) = 12.5

V = 1.27 \times 10^{-3} m^3

now when the rock is immersed into other liquid then we have

T_2 + F_b' = mg

18.3 + F_b' = 43.8

F_b' = 25.5 N

now we have

\rho(1.27 \times 10^{-3})(9.81) = 25.5

\rho = 2047 kg/m^3

4 0
3 years ago
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