The layer of electrically charged molecules and atoms which spans 40-250 miles above ground called ionosphere causes the display of the aurora and the reflection of radio waves back to earth.
Answer:
lift per meter of span = 702 N/m
Explanation:
See attached pictures.
Answer:
a) 6.9*10^14 Hz
b) 9*10^-12 T
Explanation:
From the question, we know that
435 nm is given as the wavelength of the wave, at the same time, we also know that the amplitude of the electric field, E(max) has been given to be 2.7*10^-3 V/m
a)
To find the frequency of the wave, we would be applying this formula
c = fλ, where c = speed of light
f = c/λ
f = 3*10^8 / 435*10^-9
f = 6.90*10^14 Hz
b) again, to find the amplitude of the magnetic field, we would use this relation
E(max) = B(max) * c, magnetic field amplitude, B(max) =
B(max) = E(max)/c
B(max) = 2.7*10^-3 / 3*10^8
B(max) = 9*10^-12 T
c) and lastly,
1T = 1 (V.s/m^2)
Answer:
It will take you 30.8 s to travel the 120 m of the ramp.
Explanation:
Hi there!
The equation for the position of an object moving in a straight line is:
x = x0 + v * t
Where:
x = position at time t
x0 = initial position
v = velocity
t = time
In this case, we will consider the start of the ramp as the origin of our reference system so that x0 = 0.
Now, let´s calculate the speed of the person walking on the ground:
x = v * t
120 m = v * 72 s
v = 120 m / 72 s
v = 1.7 m/s
If you walk on the ramp with that speed, your total speed will be your walking speed plus the speed of the ramp because both are in the same direction. Then, using the equation for the position:
x = v * t
In this case, v = speed of the ramp + walking speed
v = 2.2 m/s + 1.7 m/s = 3.9 m/s
120 m = 3.9 m/s * t
t = 120 m / 3.9 m/s = 30.8 s
It will take you 30.8 s to travel the 120 m
Answer:
A) t = 4.40 s
, B) v = 23.86 m / s
, c) v_y = - 43.12 m / s
, D) v = 49.28 m/s
Explanation:
This is a projectile throwing exercise,
A) To know the time of the stone in the air, let's find the time it takes to reach the floor
y = y₀ + 
t - ½ g t²
as the stone is thrown horizontally v_{oy} = 0
y = y₀ - ½ g t²
0 = y₀ - ½ g t²
t = √ (2 y₀ / g)
t = √ (2 95 / 9.8)
t = 4.40 s
B) what is the horizontal velocity of the body
v = x / t
v = 105 / 4.40
v = 23.86 m / s
C) The vertical speed when it touches the ground
v_y = - g t
v_y = 0 - 9.8 4.40
v_y = - 43.12 m / s
the negative sign indicates that the speed is down
D) total velocity just hitting the ground
v = vₓ i ^ + v_y j ^
v = 23.86 i ^ - 43.12 j ^
Let's use Pythagoras' theorem to find the modulus
v = √ (vₓ² + v_y²)
v = √ (23.86² + 43.12²)
v = 49.28 m / s
we use trigonometry for the angle
tan θ = v_y / vₓ
θ = tan⁻¹ (-43.12 / 23.86)
θ = -61
