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mr_godi [17]
3 years ago
6

The theoretical line perpindicular to the surface where a light ray hits a mirror is called the

Physics
1 answer:
valkas [14]3 years ago
3 0
That's called the "normal" to the surface at that point.
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Why is visible light safe to humans ?
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Visible light is the range of electromagnetic waves that humans can see. Anything that glows or gives off light makes waves of what we call visible light. The sun, light bulbs, candles and fire are all things that people automatically think of when it comes to light, but visible light comes from many sources and in many colors. Some other sources of visible light include: television and computer screens, glow sticks, and fireworks

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A sphere is filled with air. If the volume of the sphere is increasing at a rate of 569 cubic inches per minute, what is the rat
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What problem did the crew of Biosphere 2 face?
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What role do currents play in transporting heat? How does water temperature affect land nearby?
yarga [219]

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7 0
4 years ago
8. In the billiard ball room at the basement of Memorial Union, two identical balls are traveling toward each other along a stra
mel-nik [20]

Answer:

- Ball 1 will move backward at 7.89 m/s

- Ball 2 will move forward at 4.67 m/s

Explanation:

In an elastic collision, both the total momentum and the total kinetic energy of the system are conserved.

The conservation of the momentum can be written as:

m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2

where

m_1 is the mass of ball 1

m_2 is the mass of ball 2

u_1 is the initial  velocity of ball 1

u_2 is the initial velocity of ball 2

v_1 is the final velocity of ball 1

v_2 is the final velocity of ball 2

The conservation of kinetic energy can be written as

\frac{1}{2}m_1 u_2^2 + \frac{1}{2}m_2 u_2^2 = \frac{1}{2}m_1 v_1^2 + \frac{1}{2}m_2 v_2^2

Working together the two equations, it is possible to find two expressions for the final velocities in terms of the initial velocities:

v_1=\frac{m_1 -m_2}{m_1 +m_2}u_1+\frac{2m_2}{m_1+m_2}u_2\\v_2=\frac{2m_1}{m_1+m_2}u_1 -\frac{m_1 -m_2}{m_1 +m_2}u_2

In this problem we have:

m_1 = m_2 = m since the mass of the two balls is identical

u_1=+4.67 m/s is the initial velocity of ball 1

u_2=-7.89 m/s is the initial velocity of ball 2

Substituting into the equations, we find the final velocities:

v_1=\frac{2m}{m+m}u_2=u_2 =-7.89 m/s\\v_2=\frac{2m}{m+m}u_1=u_1=+4.67 m/s

Therefore:

- Ball 1 will move backward at 7.89 m/s

- Ball 2 will move forward at 4.67 m/s

7 0
4 years ago
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