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amm1812
3 years ago
14

If a dog walks north for 10 meters and then east for 10 meters, what is the direction of its displacement?

Physics
1 answer:
Katyanochek1 [597]3 years ago
5 0

The direction of its displacement wil be

c.northeast

In fact, the dog walks north for 10 meters and east for another 10 meters. The path of the dog can be represented with two vectors, A pointing north (of magnitude 10 meters) and B pointing east (of magnitude 10 meters). The direction of the resultant vector (due to east) will be given by

tan \theta =\frac{A}{B}=\frac{10}{10}=1

\theta=tan^{-1} (1)=45^{\circ}

and the direction will be north-east.

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ahrayia [7]

25 volts

Explanation:

Use Ohm's law to find the potential drop:

V = IR

= (0.5 A)(50 ohms)

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6 0
2 years ago
Which of the following is the most usable form of nitrogen to plants?
tresset_1 [31]
Ammonia because it doesn't have nitrogen
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3 years ago
Unpolarized light with an average intensity of 845 W/m2 enters a polarizer with a vertical transmission axis. The transmitted li
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The concept to develop this problem is the Law of Malus. Which describes what happens with the light intensity once it passes through a polarized material.

Mathematically this can be expressed as

I = I_0 cos^2\theta

Where

I = New intensity after pass through the Polarizer

I_0= Original intensity

\theta = Indicates the angle between the axis of the analyzer and the polarization axis of the incident light.

When the light passes perpendicularly through the first polarizer, the light intensity is reduced by half which will cause the intensity to be 225W / m ^ 2 at the output of the new polarizer, mathematically:

I= \frac{I_0}{2} cos^2\theta

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Solving to find the angle we have

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5 0
3 years ago
A block and tackle pulley system of 6 pulley uses 300N to overcome 1200N.find efficiency
Fittoniya [83]

Answer:

66.7%

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There are 6 pulleys, so the mechanical advantage is 6.

The theoretical force needed to overcome 1200 N is therefore:

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4 0
3 years ago
Electrons with energy of 25 eV have a wavelength of ~0.25 nm. If we send these electrons through the same two slits (d = 0.16 mm
kupik [55]

Answer:

The spacing is 5.15 μm.

Explanation:

Given that,

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Distance D=3.3 m

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Using formula of width

\beta=\dfrac{\lambda D}{d}

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\beta=\dfrac{0.25\times10^{-9}\times3.3}{0.16\times10^{-3}}

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\beta=5.15\ \mu m

Hence, The spacing is 5.15 μm.

7 0
3 years ago
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