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3 years ago

If a dog walks north for 10 meters and then east for 10 meters, what is the direction of its displacement?

Physics

1 answer:

Katyanochek1 [597]3 years ago

5 0

The direction of its displacement wil be

c.northeast

In fact, the dog walks north for 10 meters and east for another 10 meters. The path of the dog can be represented with two vectors, A pointing north (of magnitude 10 meters) and B pointing east (of magnitude 10 meters). The direction of the resultant vector (due to east) will be given by

$tan \theta =\frac{A}{B}=\frac{10}{10}=1$

$\theta=tan^{-1} (1)=45^{\circ}$

and the direction will be north-east.

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After adding them, you will get the reciprocal again and then compute for the value. The problem says that there are 4 resistors in the circuit that have a resistance of 75.

$\frac{1}{R_{T}} = \frac{1}{75}+\frac{1}{75}+\frac{1}{75}+\frac{1}{75}$

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