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tekilochka [14]
3 years ago
10

A shell is fired from the ground with an initial speed of 1500m/s at an angle of 35 degrees to the horizontal. Neglecting air re

sistance, find
a. the shell's horizontal range

b. the amount of time the shell is in motion
Physics
1 answer:
erik [133]3 years ago
6 0

Answer:

the shells horizontal is in the motion

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If two objects, like the eggs in the video, experience the same change in momentum but over time periods of
antoniya [11.8K]

Explanation:

what is the force

ican't under stand these question

4 0
2 years ago
A copper transmission cable 170 km long and 10.0 cm in diameter carries a current of 100 A .
Bond [772]

Answer:

a = = 37.2V

b = 13.39MJ

Explanation:

Given that

L = 170 × 10³

r = d/2

= 10cm / 2 = 5 cm

current I = 100A

we are to find the potential drop across the cable

so, we can use ohm’s law

V = IR = I (ρL/A)

ρ = resistivity of the copper

= 1.72 × 10⁻⁸ Ω.m

A = πr²

V = I(ρL/πr²)

= 100 (( 1.72 × 10⁻⁸ * 170 × 10³) / ( π * 0.05²))

= 37.2V

(b)

Energy (loss) = Pt

Enery (loss) = IVt

 3600s per hour

= (100A)(37.2V)(3600s)

= 13.39MJ

8 0
4 years ago
When reading the printout from a laser printer, you are actually looking at an array of tiny dots.
solniwko [45]

Answer:

The value is y  = 3.097 * 10^{-5} \  m

Explanation:

From the question we are told that

The diameter of the pupil is d_p  =  4.2 \ mm  =  4.2 *10^{-3} \  m

The distance of the page from the eye d =  29 \  cm  =  0.29 \  m

The wavelength is \lambda  =  500 \ nm =  500 *10^{-9} \  m

The refractive index is n_r =  1.36

Generally the minimum separation of adjacent dots that can be resolved is mathematically represented as

y  = [ \frac{1.22 *  \lambda }{d_p * n_r } ]* d

         y  = [ \frac{1.22 *  500 *10^{-9} }{4.2 *10^{-3} * 1.36} ]* 0.29

         y  = 3.097 * 10^{-5} \  m

7 0
3 years ago
Please help on this one?
otez555 [7]

help me w mine and ill try to help with yours


3 0
3 years ago
The force of gravity on a 1 kg object on the Earth's surface is approximately 9.8 N. For the same object in low-earth orbit arou
mojhsa [17]

Answer:

g = 8.61 m/s²

Explanation:

distance of the International Space Station form earth is 200 Km

mass of the object = 1 Kg

acceleration due to gravity on earth = 9.8 m/s²

mass of earth = 5.972 x 10²⁴ Kg

acceleration due to gravity = ?

r = 6400 + 200 = 6800 Km = 6.8 x 10⁶ n

using formula

 g = \dfrac{GM}{r^2}

 g = \dfrac{6.67\times 10^{-11}\times 5.972\times 10^24}{(6.8\times 10^6)^2}

        g = 8.61 m/s²

3 0
3 years ago
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