1)
y = kx
-12 = k(9)
k = -4/3
y = (-4/3)(-4)
y = 16/3
2)
y = kx
8 = 20k
k = 2/5
y = (2/5)(10)
y = 4
3)
y= kx
-6 = k(-14)
k = 3/7
-4 = (3/7)x
-4(7/3) = x
x = -28/3
Answer: 2.29
Step-by-step explanation:
By using differential equations' concept, we get that there is no sugar in the beginning.
<h3>What is a differential equation?</h3>
A differential equation is an equation that connects the derivatives of one or more unknown functions.
Given:
Pure water = 2840 litres
sugar = 0.01kg per liter
Rate of sugar entering the tank = 4liter/min
New solution drains out at the rate = 4 litre/min
To find: sugar in the beginning.
Finding:
(a) In the beginning, the tank contains only pure water and no solution of water with sugar.
Hence, the sugar is null for t = 0.
To learn more about differential equations, refer to the link: brainly.com/question/1164377
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Answer:
subtract 2 from both sides
Step-by-step explanation:
if you subtract 2 from both sides you will get k=3
Step-by-step explanation: