When the moon faces earth a solar eclipse happens :-)
Answer:
Work and Kinetic Energy
A B
3. A 0.180 kg balls falls 2.5 m. How much work does the force of gravity do on the ball? 4.41 J
4. A forklift raises a box 1.2 m doing 7.0 kJ of work on it. What is the mass of the box? 595.24 kg
5. How much work does the force of gravity do when a 25 N object falls a distance of 3.5 m? 87.5 J
Explanation:
'A' is correct. B, C, and D are false statements.
Answer:
1.25kg
Explanation:
Simply multiply volume and density together
(a) Let's convert the final speed of the car in m/s:

The kinetic energy of the car at t=19 s is

(b) The average power delivered by the engine of the car during the 19 s is equal to the work done by the engine divided by the time interval:

But the work done is equal to the increase in kinetic energy of the car, and since its initial kinetic energy is zero (because the car starts from rest), this translates into

(c) The instantaneous power is given by

where F is the force exerted by the engine, equal to F=ma.
So we need to find the acceleration first:

And the problem says this acceleration is constant during the motion, so now we can calculate the instantaneous power at t=19 s: