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Which of the following is NOT the name of an air mass? . . A. tepid moist. B. cool moist. C. warm moist . D. hot dry. E. warm dr

g100num [7]

None of the above are the name of an air mass. This is probably a trick question.

4 0

4 years ago

A baton twirler has a baton of length 0.36 m with masses of 0.48 kg at each end. Assume the rod itself is massless. The rod is f

AleksAgata [21]

Answer:

Part a)

When rotated about the mid point

$\tau = 0.021Nm$

Part b)

When rotated about its one end

$\tau = 0.042 Nm$

Explanation:

As we know that the angular acceleration of the rod is rate of change in angular speed

so we will have

$\alpha = \frac{\Delta \omega}{\Delta t}$

$\alpha = \frac{2.4 - 0}{3.6}$

$\alpha = 0.67 rad/s^2$

Part a)

When rotated about the mid point

$I = 2mr^2$

$I = 2(0.48)(0.18)^2$

$I = 0.0311 kg m^2$

now torque is given as

$\tau = 0.0311 (0.67)$

$\tau = 0.021Nm$

Part b)

When rotated about its one end

$I = m(2r)^2$

$I = (0.48)(0.36)^2$

$I = 0.0622 kg m^2$

now torque is given as

$\tau = (0.0622)(0.67)$

$\tau = 0.042 Nm$

3 0

3 years ago

What happens when a roller coaster car moves down from the top of a hill?

VLD [36.1K]

When the roller coaster moves down from the top of the hill, all of its stored potential energy is converted into kinetic energy to move it and when it goes back up the hill it turns kinetic into potential.

3 0

3 years ago

Read 2 more answers

You will be colliding two carts in this lab. Select all the systems for which you predict the total momentum of the system will

baherus [9]

From the momentum conservation we know that the initial momentum is equal to the final momentum. The momentum in a singular way can be defined as the product between the mass and the velocity of an object. In the presented system, however, there are two objects, therefore the mass of both and the speed of both, before and after the collision must be taken into account. Mathematically we could describe this as

$m_1u_1+m_2u_2 = m_1v_1+m_2v_2$

Here,

$m_{1,2}$ = Mass of each object

$u_{1,2}$ = Initial velocity of each object

$v_{1,2}$ = Final velocity of each object

From here we can realize that it is necessary to use the system on both cars to be able to predict what will happen either with their masses, or their speeds.

The correct answer is C.

6 0

3 years ago

Find the gravitational potential energy of an 84 kg person standing atop Mt. Everest at an altitude of 8848 m. Use sea level as

djverab [1.8K]

Answer:

$E=7.28\times 10^6\ J$

Explanation:

Given that,

Mass of a person, m = 84 kg

The person is standing at a top of Mt. Everest at an altitude of 8848 m

We need to find the gravitational potential energy of the person. We know that the gravitational potential energy is possessed due to the position of an object. It is given by :

E = mgh, g is the acceleration due to gravity

$E=84\ kg\times 9.8\ m/s^2\times 8848\ m\\\\E=7283673.6\ J\\\\E=7.28\times 10^6\ J$

So, the gravitational potential energy of the person is $7.28\times 10^6\ J$

6 0

3 years ago