Answer:
4.4857 seconds
No
Explanation:
L = Length of the pendulum = 5 m
g = Acceleration due to gravity = 9.81 m/s²
Time period is given by
The optimum time interval in between the pushes is 4.4857 seconds
It can be seen that the mass of the child is not used in the formula and hence changing the mass would not result in a different time period.
The length of the pendulum and the acceleration of gravity of the planet determines the time period.
Answer:
Pushes and pulls refer to the force that attracts or repels certain other materials without actually touching them.
Explanation:
Pushes and pulls are the forces exerted by the magnet on certain materials around it without, actually touching them. This push and pull is exerted through a region around the magnet called its magnetic field. The strength of this push and pull force is determined by, the strength of the magnetic field. A strong push or pull force is exerted by a strong magnetic field, and in turn a strong magnet and, a weak push and pull force is exerted by a weak magnetic field and, in turn a weak magnet. A push force is a repulsion while a pull force is an attraction. When a magnetic object is in the region of the magnetic field, it either attracts or is repelled away from the source of the magnetic field.
The shear connectors must transfer axial shear stress completely. The minimum slip value is needed to limit the maximum slip at the ultimate limit state.
<h3>
What is shear connection?</h3>
A shear connection is a type of join which allows the transfer of shear forces between two members of beams or truss.
The shear connectors are used in composite beam is to transfer the longitudinal shear stresses at the interface between the steel beam and the concrete slab.
The slip requirements are less than in a propped beam. The higher strains resulting in the bare steel section carrying the construction
Thus, minimum slip value is needed to limit the maximum slip at the ultimate limit state.
Learn more about shear connection.
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Answer:
Explanation:
Therefore, the speed of the car is 63m/s after 8 seconds while accelerating at it maximum capability.
F = force applied to hold the weight of the bowling ball = weight of the bowling ball = 75 N
d = distance through which the bowling ball is moved horizontally = 10 meter
θ = angle between the force in vertically upward direction and displacement in horizontal direction = 90
W = work done on the bowling ball
work done on the bowling ball is given as
W = F d Cosθ
inserting the values
W = (75) (10) Cos90
W = (75) (10) (0)
W = 0 J