Answer:
This is the answer that i assume because that's the only method we can use here
The answer is A vaporization
Answer:
0.647 nC
Explanation:
The force experienced by a charge due to the presence of an electric field is given by
![F=qE](https://tex.z-dn.net/?f=F%3DqE)
where
q is the charge
E is the magnitude of the electric field
In this problem, each antenna is modelled as it was a single point charge, experiencing a force of
![F=5.50\mu N = 5.50\cdot 10^{-6} N](https://tex.z-dn.net/?f=F%3D5.50%5Cmu%20N%20%3D%205.50%5Ccdot%2010%5E%7B-6%7D%20N)
Therefore, if the electric field magnitude is
![E=8.50 kN/C = 8500 N/C](https://tex.z-dn.net/?f=E%3D8.50%20kN%2FC%20%3D%208500%20N%2FC)
Then the charge on each antenna would be
![q=\frac{F}{E}=\frac{5.50\cdot 10^{-6} N}{8500 N/C}=6.47\cdot 10^{-10} C = 0.647 nC](https://tex.z-dn.net/?f=q%3D%5Cfrac%7BF%7D%7BE%7D%3D%5Cfrac%7B5.50%5Ccdot%2010%5E%7B-6%7D%20N%7D%7B8500%20N%2FC%7D%3D6.47%5Ccdot%2010%5E%7B-10%7D%20C%20%3D%200.647%20nC)
Maximum and minimum of two concurrent forces occur when the forces are collinear. Maximum occurs when they are in the same direction, and minimum occurs when they are opposite in directions.
This reduces the problem to a sum an difference problem.
A+B=45
A-B=5
So
A=(45+5)/2=25
B=(45-5)/2=20
Check:
maximum=25+20=45
minimum=25-20=5
ok
ANSWER: 170 Feet
REASON: with good breaks and a dry road your car should stop and skip 170 feet, with perception and reaction time of stopping you should stop within 170 feet