The concentration of a solution that contains 70g of H2SO4 in 0,28 dm³ of solution is?
1 answer:
Taking into account the definition of molarity, the concentration of a solution that contains 70 g of H₂SO₄ in 0,28 dm³ of solution is 2.5510 .
Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.
The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:
Molarity is expressed in units .
In this case, you have:
- number of moles= 70 g×
= 0.7143 moles, where 98 g/mole os the molar mass of H₂SO₄
- volume= 0.28 dm³= 0.28 L (being 1 dm³= 1 L)
Replacing in the definition of molarity:
Solving:
<u><em>Molarity= 2.5510 </em></u>
Finally, the concentration of a solution that contains 70 g of H₂SO₄ in 0,28 dm³ of solution is 2.5510 .
Learn more about molarity:
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Answer:
Δt = 5.85 s
Explanation:
For this exercise let's use Faraday's Law
emf = - d fi / dt
= B. A
\phi = B A cos θ
The bold are vectors. It indicates that the area of the body is A = 0.046 m², the magnetic field B = 1.4 T, also iindicate that the normal to the area is parallel to the field, therefore the angle θ = 0 and cos 0 =1.
suppose a linear change of the magnetic field
emf = - A
Dt = - A
the final field before a fault is zero
let's calculate
Δt = - 0.046 (0- 1.4) / 0.011
Δt = 5.85 s