Question

The concentration of a solution that contains 70g of H2SO4 in 0,28 dm³ of solution is?​

Answer 1

Taking into account the definition of molarity, the concentration of a solution that contains 70 g of H₂SO₄ in 0,28 dm³ of solution is 2.5510 $\frac{moles}{L}$.

Definition of molarity

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

$Molarity=\frac{number of moles}{volume}$

Molarity is expressed in units $\frac{moles}{L}$.

This case

In this case, you have:

• number of moles= 70 g×$\frac{1 mole}{98 g}$= 0.7143 moles, where 98 g/mole os the molar mass of H₂SO₄
• volume= 0.28 dm³= 0.28 L (being 1 dm³= 1 L)

Replacing in the definition of molarity:

$Molarity=\frac{0.7143 moles}{0.28 L}$

Solving:

Molarity= 2.5510 $\frac{moles}{L}$

Finally, the concentration of a solution that contains 70 g of H₂SO₄ in 0,28 dm³ of solution is 2.5510 $\frac{moles}{L}$.

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