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tiny-mole [99]
3 years ago
6

An electrochemical cell is constructed using two half-cells: Al(s) in Al(NO2)3(aq) and Cu(s) in Cu(NO3)2(aq). The two half cells

are connected by a KNO3 salt bridge and two copper wires from the electrodes to a voltmeter. Based on their respective standard reduction potentials, which half-cell is the cathode?
Chemistry
1 answer:
wlad13 [49]3 years ago
4 0

Answer:

Cu(s) in Cu(NO₃)₂(aq)

Explanation:

The standard reduction potential (E°) is the energy necessary to reduce the atom in a redox reaction. When an atom reduces it gains electrons from other than oxides. As higher is E°, easily it will reduce. The substance that reduces is at the cathode of a cell, where the electrons go to, and the other that oxides are at the anode of the cell.

The standard reduction potentials from Al(s) and Cu(s) are, respectively, -1.66V and +0.15V, so the half-cell of Cu(s) in Cu(NO₃)₂(aq) is the cathode.

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The volume of a sample of gas, initially at 25 °C and 158 mL, increases to
Artist 52 [7]

Answer:

The final temperature = 848.7 K or 575.7 °C

Explanation:

Step 1: Data given

Temperature = 25.0 °C = 298 K

Volume = 158 mL = 0.158 L

The volume increases to 450 mL = 0.450 L

The pressure is constant

Step 2: Calculate the final temperature

V1/T1 = V2/T2

⇒with V1 = the initial volume = 0.158 L

⇒with T1 = the initial temperature = 298 K

⇒with V2 = the increased volume = 0.450 L

⇒with T2 = the new temperature = TO BE DETERMINED

0.158 L / 298 K = 0.450 L / T2

T2 = 0.450 L / (0.158L/298K)

T2 = 848.7 T

The final temperature = 848.7 K or 575.7 °C

5 0
3 years ago
How many grams of glucose (C6H12O6) can be formed from 22 grams of CO2?
Shkiper50 [21]
The catabolism of glucose has an equation of C6H12O6 + 6O2 = 6CO2 +6 H20. Hence for every mole of glucose, 6 moles of CO2 is produced. Given 22 grams of CO2, that is 0.5 mol CO2, we multiply this by 1/6, we get the number of moles of glucose equal to 1/12 mol. The mass of glucose needed is obtained by multiplying this by molar mass of glucose which is 180 g/mol. This is equivalent 15 grams of glucose.
8 0
2 years ago
I NEED HELP PLEASE ASAP!! :)<br><br> How many molecules are represented by 3CO2?
andriy [413]
9. 3 Carbon and 6 Oxygen
7 0
3 years ago
Read 2 more answers
How many grams are in 88.1 moles of magnesium?
rjkz [21]
For getting the result of this problem, the knowledge of periodic table is very important. From the periodic table we come to know that. The knowledge of atomic mass of magnesium is also required to solve the problem.
1 mole of magnesium = 24.3 gm
88.1 moles of magnesium = (24.3 * 88.1) gms
                                           = 2140.83 gms
So 2140.83 grams are there in 88.1 moles of magnesium.
4 0
3 years ago
What is the molar mass of KOH?
Julli [10]
<h3>Answer:</h3>

56.11 g/mol

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Compound] KOH

<u>Step 2: Identify</u>

[PT] Molar Mass of K - 39.10 g/mol

[PT] Molar Mass of O - 16.00 g/mol

[PT] Molar Mass of H - 1.01 g/mol

<u>Step 3: Find</u>

39.10 + 16.00 + 1.01 = 56.11 g/mol

5 0
2 years ago
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