Energy from SUNLIGHT + CO2(g) + H2O(l) = C6H12O6 (glucose) + O2(g)
The above is unbalanced, but it shows that sunlight is on the left side of the equation.
Sunlight provides the energy for the reaction to take place, without it nothing would really happen. Therefore it is an INPUT into the equation, thus it is on the left side. Outputs are placed on the right side of the equation.
Answer:
= 24 square units
Explanation:
The area of a rhombus is given by the formula;
Area = pq/2
Where p and q are the diagonals of the rhombus.
In this case; p = 6 and q = 8
Therefore;
Area = (6×8)/2
= 24 square units
Answer:
d. 99.63% and 0.364%, respectively
Explanation:
The average mass of a nitrogen atom is 14.006 amu
14N-14.00307 amu with 0.9963 fractional abundance
1SN- 15.000108 amu with 0.00364 fractional abundance.
The relative abundance definition in chemistry is the percentage of a particular isotope that occurs in nature. The atomic mass listed for an element on the periodic table is an average mass of all known isotopes of that element.
In this problem, the fractional abundance has areaady been given. All we need to do now is convert them to percentage abundance.
14N-14.00307 = 0.9963* 100% = 99.63%
1SN- 15.000108 = 0.00364 * 100% = 0.364%
