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FinnZ [79.3K]
3 years ago
13

Which of the following correctly compares a scientific investigation to a demonstration

Physics
2 answers:
VikaD [51]3 years ago
8 0
Without options I can simply compare a scientific investigation to a demonstration:

<span>An investigation is a process when you are answering a question about the answer of which you do not know while a demonstration is a display or show of how something happens, when you already know the outcome.
</span>
Evgen [1.6K]3 years ago
5 0

An investigation is a process of answering a question; a demonstration shows the process of how something happens

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A satellite of mass 1000kg is in a circular orbit around a planet. The centripetal acceleration of the satellite in its orbit is
ludmilkaskok [199]

Answer: 5000N

Explanation:

The basic principle of a circular orbit is that Fg = m × ac, so as we have the mass and the centripetal acceleration (also called normal acceleration) we just have to operate. Fg = 1000kg × 5m/s² = 5000N

8 0
3 years ago
Based on the law of conservation of energy, how can we reasonably improve a machine’s ability to do work?
kifflom [539]
Based on the law of conservation of energy, we know that we can't create energy, machines can only convert one type of energy into another. So, if we want to improve a machines's ability then we need to reduce it's loss energy (part of energy which is useless). Out of all the options only Option C fits best with it.

In short, Your Answer would be Option C

Hope this helps!
6 0
3 years ago
Read 2 more answers
What is the closed physical system?
Alexus [3.1K]
Answer:D
A system where matter and energy can not enter or leave the system
8 0
3 years ago
A 1.5m wire carries a 6 A current when a potential difference of 68 V is applied. What is the resistance of the wire?
ANTONII [103]

Answer:

11.3 \Omega

Explanation:

We can find the resistance of the wire by using Ohm's law:

V=RI

where

V is the voltage applied

R is the resistance

I is the current

In this problem, we know I = 6 A and V = 68 V, so we can re-arrange the equation to find the resistance of the wire:

R=\frac{V}{I}=\frac{68 V}{6 A}=11.3 \Omega

6 0
3 years ago
For both resonance curves and Fourier spectra, amplitude is plotted vs frequency, but these two types of plots are not the same.
andrey2020 [161]

Answer:

he peaks are the natural frequencies that coincide with the excitation frequencies and in the second case they are the natural frequencies that make up the wave.

Explanation:

In a resonance experiment, the amplitude of the system is plotted as a function of the frequency, finding maximums for the values ​​where some natural frequency of the system coincides with the excitation frequency.

In a Fourier transform spectrum, the amplitude of the frequencies present is the signal, whereby each peak corresponds to a natural frequency of the system.

From this explanation we can see that in the first case the peaks are the natural frequencies that coincide with the excitation frequencies and in the second case they are the natural frequencies that make up the wave.

7 0
3 years ago
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