A sailboat moves north for a distance of 10.00 km when blown by a wind from the exact south with a force of 5.00 x 10^4 n. how m
1 answer:
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Answer:
<em>(a) t = 4.52 sec</em>
<em>(b) X = 1,156.49 m</em>
Explanation:
<u>Horizontal Launching </u>
If an object is launched horizontally, its initial speed is zero in the y-coordinate and the horizontal component of the velocity remains the same in time. The distance x is computed as
.
(a)
The vertical component of the velocity starts from zero and gradually starts to increase due to the acceleration of gravity as follows
This means the vertical height is computed by
Where is the initial height. Our fighter bomber is 100 m high, so we can compute the time the bomb needs to reach the ground by solving the above equation for t knowing h=0
(b)
We now compute the horizontal distance knowing
Explanation:
A bearing if an angle is measured clockwise from north direction.
e.g Below the bearing of B from A is 025. (3 figures are always given). the bearing of A from B is 205°.
