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Yuri [45]
3 years ago
8

When catching a baseball, the ball applies a force of 39.6 N to a  catcher's glove.  If the work done on the catchers glove is 4

7.5 J  what is the recoil (travel of)  on the mitt?
Physics
1 answer:
cricket20 [7]3 years ago
4 0

Answer:

d = 1.19 m

Explanation:

Given that,

The force applied by the ball, F = 39.6 N

The work done on the catchers glove is 47.5 J

We need to find the distance traveled by the ball. We know that,

Work done, W = Fd

Where

d is the distance traveled

d=\dfrac{W}{F}\\\\d=\dfrac{47.5 }{39.6 }\\\\d=1.19\ m

So, it will cover 1.19 m.

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What is the distance in m between lines on a diffraction grating that produces a second-order maximum for 775-nm red light at an
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Answer:

The distance is d =  1.747 *10^{-6} \ m  

Explanation:

From the question we are told that  

       The order of maximum diffraction is  m =  2

         The wavelength is   \lambda  =  775 nm  = 775 * 10^{-9}  \ m

         The angle is  \theta =  62.5^o

Generally the   condition for  constructive  interference for diffraction grating  is mathematically represented as

          dsin \theta  =  m *  \lambda

where  d is  the distance between the lines on a  diffraction grating

     So  

            d =  \frac{m *  \lambda  }{sin (\theta  )}

substituting values  

           d =  \frac{2  *  775 *1^{-9} }{sin ( 62.5  )}

          d =  1.747 *10^{-6} \ m

   

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3 years ago
What is the weight of a ring tailed lemur that has a mass of 10 kg? Use w = mg (g = -9.8 m/s^2)
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m = 10 kg

g = -9.8 m/s2

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What's the toughest animal in the world
eduard

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A thin uniform rod of mass M and length L is bent at its center so that the two segments are perpendicular to each other. Find i
serg [7]

Answer:

\frac{1}{12}ML^2

Explanation:

The moments of the whole object is the sum of the moments of the 2 segments of rod at their ends of which length is L/2 and mass M/2:

I = 2I_{end} = 2\frac{1}{3}\frac{M}{2}\left(\frac{L}{2}\right)^2

I = \frac{1}{3}M\frac{L^2}{4}

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