<span>Answer:
Anthracene is a solid polycyclic aromatic hydrocarbon (PAH) which has the formula as C14H10, consisting of three fused benzene rings. It is a component of coal tar. Anthracene is used in the production of the red dye alizarin and other dyes.</span>
The extra conversion of concentration of reactant and product should be zero in order to attaining equlibrium state.
<h3>What is equilibrium?</h3>
Chemical equilibrium refers to the state in which both the reactants and products are present in equal concentrations or amount. In equlibrium, same amount of reactant is converted into product and product into reactant.
So we can conclude that the extra conversion of concentration of reactant and product should be zero in order to attaining equlibrium state.
Learn more about equilibrium here: brainly.com/question/517289
<h2>The required "option is b) hydrogen bonds must be broken to raise its temperature.</h2>
Explanation:
- Water has high specific heat due to hydrogen bonds present in it.
- The Ionisation of water does not affect the specific heat of the water.
- On decreasing the temperature, there is the formation of bonds hence option (d) is wrong.
- On increasing the temperature, there is the breaking of bonds hence option (b) is correct.
<h3>
Answer:</h3>
Lead-205 (Pb-205)
<h3>
Explanation:</h3>
<u>We are given;</u>
We are supposed to identify its product after an alpha decay;
- Polonium-209 has a mass number of 209 and an atomic number of 84.
- When an element undergoes an alpha decay, the mass number decreases by 4 while the atomic number decreases by 2.
- Therefore, when Po-209 undergoes alpha decay it results to the formation of a product with a mass number of 205 and atomic number of 82.
- The product from this decay is Pb-205, because Pb-205 has a mass number of 205 and atomic number 82.
- The equation for the decay is;
²⁰⁹₈₄Po → ²⁰⁵₈₂Pb + ⁴₂He
- Note; An alpha particle is represented by a helium nucleus, ⁴₂He.
Answer: 600 mL
Explanation:
Given that;
M₁ = 5.85 m
M₂ = 1.95 m
V₁ = 200 mL
V₂ = ?
Now from the dilution law;
M₁V₁ = M₂V₂
so we substitute
5.85 × 200 = 1.95 × V₂
1170 = 1.95V₂
V₂ = 1170 / 1.95
V₂ = 600 mL
Therefore final volume is 600 mL
