How much will Alexis earn if she earns $8.60 per hour, works 8 hours, and has payroll deductions of $16.51?

Complete the slope-intercept form of the linear equation that represents the relationship in the table.

nevsk [136]

According to the given table, the slope-intercept equation of the line is given by:

$y = -2x + 1$

The equation of a line, in slope-intercept form, is given by:

$y = mx + b$

In which:

The slope is m.

The intercept is b.

In this problem, we are given two points, (3,-5) and (-2,5).

The slope is given by change in y divided by change in x, hence:

$m = \frac{5 - (-5)}{-2 - 3} = -2$

Hence:

$y = -2x + b$

Point (3,-5) means that when $x = 3, y = -5$ , which is used to find b.

$y = -2x + b$

$-5 = -2(3) + b$

$b = 1$

Hence, the equation of the line is:

$y = -2x + 1$

A similar problem is given at brainly.com/question/24685547

6 0

2 years ago

Translate this phrase into an algebraic expression.

Alekssandra [29.7K]

4/x+10

(4 divided by x + 10)

7 0

3 years ago

HELP NEEDED ASAP!! Amani computed in a two-way table the relative frequencies of sales of homes listed with two different real e

guajiro [1.7K]

The answer is c.

When you look at the data, in the first column, the frequency of sales of both are similar. Even the second column shows similar data. Association is determined if there is a significant difference between the data in each column/row depending on what you are aiming to answer.

In this case, we look at it per column because you want to compare the frequencies of sales of each company which are aligned by columns. So we know to look at the columns and not the rows.

8 0

3 years ago

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After a college football team once again lost a game to their archrival, the alumni association conducted a survey to see if alu

valentina_108 [34]

Answer:

P-value for this hypothesis test is 0.00175.

Step-by-step explanation:

We are given that the alumni association conducted a survey to see if alumni were in favor of firing the coach.

A simple random sample of 100 alumni from the population of all living alumni was taken. Sixty-four of the alumni in the sample were in favor of firing the coach.

Let p = proportion of all living alumni who favored firing the coach

SO, Null Hypothesis, $H_0$ : p = 0.50 {means that the majority of alumni are not in favor of firing the coach}

Alternate Hypothesis, $H_A$ : p > 0.50 {means that the majority of alumni are in favor of firing the coach}

The test statistics that will be used here is One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of the alumni in the sample who were in favor of firing the coach = $\frac{64}{100}$ = 0.64

n = sample of alumni = 100

So, test statistics = $\frac{0.64-0.50}{{\sqrt{\frac{0.64(1-0.64)}{100} } } } }$

= 2.92

Now, P-value of the hypothesis test is given by ;

P-value = P(Z > 2.92) = 1 - P(Z $\leq$ 2.92)

= 1 - 0.99825 = 0.00175

Therefore, the P-value for this hypothesis test is 0.00175.

4 0

3 years ago

HOW DO U USE A MODEL WHEN USING PERCENTAGES

larisa86 [58]

You can model a percent many ways. Compare fractions, decimals and percents using area models. You can also use a pi chart, bar graph, and so many other graphs when using percentages. Hope this helps you.

4 0

3 years ago

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