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Deffense [45]
3 years ago
14

A chemist takes 50-gram sample of sulfur powder that has a melting point of 115.2 °C. What is the melting point of a 100-gram sa

mple of sulfur powder?
A. 115.2 °C since melting point is an extensive property
B. 115.2 °C since melting point is an intensive property
C. Double of 115.2 °C since melting point is an intensive property
D. Double of 115.2 °C since melting point is an extensive property
Chemistry
2 answers:
amm18123 years ago
7 0
<h2><em>B. 115.2 °C since melting point is an intensive property.</em></h2><h3><em>Hope I helped,sorry if no tho</em></h3>
JulijaS [17]3 years ago
3 0
I would say that B is the correct answer which means that the melting point would be intensive or that no matter how large or small the sample of the sulphur is, it will have a consistent melting temperature or of 115.2 degrees C. 
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liraira [26]

By looking at a periodic table, we can conclude that the molar mass of lithium is 6.94g, the molar mass of zinc is 65.38g, and the molar mass of gold is 196.97g. Each of these quantities contains 6.02×1023 atoms of that particular element. The units for molar mass are grams per mole, or g/mol.

So The answers are Lithium, Gold, Zinc

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~Zero~

3 0
2 years ago
Read 2 more answers
An unknown substance has a density of 56 g/cm3. Its volume is 3.5 cm.
postnew [5]

Answer:

<h3>The answer is 196 g</h3>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

mass = Density × volume

From the question we have

mass = 56 × 3.5

We have the final answer as

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2 years ago
Describe in general terms the structure of ionic solids such as nacl
allochka39001 [22]
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8 0
3 years ago
In the presence of oxygen, the three-carbon compound pyruvate can be catabolized in the citric acid cycle. First, however, the p
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Answer:1.

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6 0
3 years ago
The reaction below will occur in a gaseous system at STP:
WARRIOR [948]

Answer:

V = 12.5 L

Explanation:

Given data:

Volume of NO = 15.0 L

Temperature and pressure = standard

Volume of nitrogen gas produced = ?

Solution:

Chemical equation:

6NO + 4NH₃    →     5N₂ + 6 H₂O

Number of moles of NO:

PV = nRT

n = PV/RT

n = 1 atm × 15.0 L / 0.0821 atm.L /mol.K × 273.15 K

n = 15.0 atm.L / 22.43 atm.L /mol

n = 0.67 mol

now we will compare the moles of No and nitrogen gas.

              NO           :         N₂

               6             :          5

              0.67         :         5/6×0.67 = 0.56

Volume of nitrogen gas:

 PV = nRT

1 atm × V = 0.56 mol ×  0.0821 atm.L /mol.K × 273.15 K

V = 12.5 atm.L / 1 atm

V = 12.5 L

4 0
3 years ago
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