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3 years ago

Which of these is most likely to happen during a solar storm? (2 points)

Chemistry

2 answers:

Degger [83]3 years ago

8 0

Answer:

GPS positioning systems will stop functioning.

Explanation:

Solar storms are strong electromagnetic waves. These are produced on the surface of the sun, and these massive waves sometimes hit the earth's atmosphere. These waves disrupt the radio signal waves present in the earth's atmosphere and block the satellite communication to the earth. As a result, the GPS will not work. Due to its waves, the power grids stops to work. It also disturbs electricity and telephone communication. These solar storms are molten lava which produces on the sun by nuclear fusion.

emmainna [20.7K]3 years ago

7 0

Electricity grids will produce surplus power

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What shows the substance at the highest temperature?

Tcecarenko [31]

Answer:

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Explanation:

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3 years ago

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If I have 251.14 grams of citric acid and calcium bicarbonate mixture how much citrus acid do I have??

Snezhnost [94]

About 255.3 grams is the answer I believe. I just had a school work packet and had that question on it, and that is the answer that I had put on it I believe.

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4 years ago

One would not expect yeast to undergo fermentation in the presence of

Hunter-Best [27]

Answer:

Oxygen.

Explanation:

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3 years ago

How many moles of HNO3 are present if 4.90×10−2 mol of Ba(OH)2 was needed to neutralize the acid solution?

Amiraneli [1.4K]

Answer:

0.098 moles

Explanation:

Let y represent the number of moles present

1 mole of Ba(OH)₂ contains 2 moles of OH- ions.

Hence, 0.049 moles of Ba(OH)2 contains y moles of OH- ions.

To get the y moles, we then do cross multiplication

1 mole * y mole = 2 moles * 0.049 mole

y mole = 2 * 0.049 / 1

y mole = 0.098 moles of OH- ions.

1 mole of OH- can neutralize 1 mole of H+

Therefore, 0.098 moles of HNO₃ are present.

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3 years ago

Calculate the Kc for the following reaction if an initial reaction mixture of 0.500 mole of CO and 1.500 mole of H2 in a 5.00 li

Lera25 [3.4K]

Answer:

4.41

Explanation:

Step 1: Write the balanced equation

CO(g) + 3 H₂(g) = CH₄(g) + H₂O(g)

Step 2: Calculate the respective concentrations

$[CO]_i = \frac{0.500mol}{5.00L} = 0.100M$

$[H_2]_i = \frac{1.500mol}{5.00L} = 0.300M$

$[H_2O]_{eq} = \frac{0.198mol}{5.00L} = 0.0396M$

Step 3: Make an ICE chart

CO(g) + 3 H₂(g) = CH₄(g) + H₂O(g)

I 0.100 0.300 0 0

C -x -3x +x +x

E 0.100-x 0.300-3x x x

Step 4: Find the value of x

Since the concentration at equilibrium of water is 0.0396 M, x = 0.0396

Step 5: Find the concentrations at equilibrium

[CO] = 0.100-x = 0.100-0.0396 = 0.060 M

[H₂] = 0.300-3x = 0.300-3(0.0396) = 0.181 M

[CH₄] = x = 0.0396 M

[H₂O] = x = 0.0396 M

Step 6: Calculate the equilibrium constant (Kc)

$Kc = \frac{[CH_4] \times [H_2O] }{[CO] \times [H_2]^{3} } = \frac{0.0396 \times 0.0396 }{0.060 \times 0.181^{3} } = 4.41$

3 0

4 years ago