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____ [38]
3 years ago
11

Molecular compounds result from covalent bonding which are called _____

Chemistry
1 answer:
11Alexandr11 [23.1K]3 years ago
3 0
There are three which are:
dispersion/london/van der vaals forces
dipole/dipole
hydrogen bonding
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Read 2 more answers
How many grams of sodium (na ) would be needed to create a 100 millimole concentration in one liter?
Rina8888 [55]

2.3g of sodium would be needed to create a 100 millimole concentration in one liter.

Given,

Mole of Na+ = 100 millimole

As we know that,

1 millimole = 10 -³ mole

Mole of Na+ in 100 millimoles = 100 × 10 -³ mole

= 0.1mole

<h3>What is Mole? </h3>

Mole is defined as the ratio of mass of Na+ to the molar mass of sodium.

<h3>What is Molar Mass? </h3>

The molar mass is defined as the sum of the total mass in grams unit of the atoms present to make a molecule per mole.

Mole of Na+ = mass of Na + / molar mass of Na +

0.1 = mass of Na + / 22.99 gl mol

Mass of Na + = 0.1 × 22.99

= 2.299 g

Mass of Na + = 2.3 g

Thus, we calculated that 2.3g of sodium would be needed to create a 100 millimole concentration in one liter.

learn more about moles:

brainly.com/question/15209553

#SPJ4

7 0
1 year ago
Question 4 of 33
valentinak56 [21]

Answer:

The answer is Sedimentary

Explanation:

Thank you so much if that helps you!!!!

6 0
3 years ago
Magnesium chloride, MgCl2, is an important industrial chemical.
gavmur [86]

This problem is providing information about a reaction between magnesium and hydrochloric acid. However, the moles of the latter are required given 50 cm³ of a 0.2-M solution, making this problem more about the application of molarity. At the end, the answer turns out to be 0.01 mol.

<h3>Molarity:</h3>

In chemistry, we use units of concentration in order to represent the relative amounts of solute and solvent in a solution. More specifically, molarity relates the moles of the solute with the liters of solution according to:

M=\frac{n}{V}

Thus, since this problem asks for the moles of hydrochloric acid in 50 cm³ of a 0.2-M solution, we must first calculate the volume in liters with:

V=50cm^3*\frac{1L}{1000cm^3} =0.050L

To finally solve for n, moles, to obtain:

0.2mol/L=\frac{n}{0.05L} \\\\n=0.2mol/L*0.05L\\\\n=0.01mol

Learn more about molarity: brainly.com/question/9468209

8 0
2 years ago
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