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ira [324]
3 years ago
12

What are the three types of seismic waves?

Chemistry
2 answers:
Step2247 [10]3 years ago
8 0
Body waves , secondary, primary
Softa [21]3 years ago
5 0
Earthquakes generate three types of seismic waves<span>: P (primary) </span>waves<span>, S (secondary) </span>waves<span> and surface </span>waves<span>, which arrive at </span>seismic<span> recording stations one after another. Both P and S </span>waves<span>penetrate the interior of the Earth while surface </span>waves<span> do not. Due to this, P and S </span>waves<span> are known as "body </span>waves<span>".


hope that helped</span>
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The main types of chemical bonds are ________ and _______ bonds
Musya8 [376]

Answer:

covalent and ionic

Explanation:

covalent is nonmetal+nonmetal

ionic is metal+nonmetal

5 0
3 years ago
Atoms of which element have two protons and two electrons?
Len [333]
B.) Helium have <span>two protons and two electrons

Hope this helps!</span>
6 0
3 years ago
Read 2 more answers
Consider the following equilibrium: H2CO3+H2O = H3O+HCO3^-1. What is the correct equilibrium expression?
mylen [45]

Equilibrium expression is Keq = \frac{[H3O+][HCO3^-]}{[H2CO3]}\\

<u>Explanation:</u>

Equilibrium expression is denoted by Keq.

Keq is  the equilibrium constant that is defined as the ratio of concentration of products to the concentration of reactants each raised to the power its stoichiometric coefficients.

Example -

aA + bB = cC + dD

So, Keq = conc of product/ conc of reactant

Keq = \frac{[C]^c [D]^d}{[A]^a [B]^b}

So from the equation, H₂CO₃+H₂O = H₃O+HCO₃⁻¹

Keq = \frac{[H3O^+]^1 [HCO3^-]^1}{[H2CO3]^1 [H2O]^1}

The concentration of pure solid and liquid is considered as 1. Therefore, concentration of H2O is 1.

Thus,

Keq = \frac{[H3O+][HCO3^-]}{[H2CO3]}\\

Therefore, Equilibrium expression is Keq = \frac{[H3O+][HCO3^-]}{[H2CO3]}\\

4 0
3 years ago
Which of the following is a true statement?
sergejj [24]

Answer:

C

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Wind is geological therefore it is geological weathering

5 0
3 years ago
What volume is occupied by 0.109 molmol of helium gas at a pressure of 0.98 atmatm and a temperature of 307 K
KATRIN_1 [288]

Answer:

2.8 L

Explanation:

From the question given above, the following data were obtained:

Number of mole (n) = 0.109 mole

Pressure (P) = 0.98 atm

Temperature (T) = 307 K

Gas constant (R) = 0.0821 atm.L/Kmol

Volume (V) =?

The volume of the helium gas can be obtained by using the ideal gas equation as follow:

PV = nRT

0.98 × V = 0.109 × 0.0821 × 307

0.98 × V = 2.7473123

Divide both side by 0.98

V = 2.7473123 / 0.98

V = 2.8 L

Thus, the volume of the helium gas is 2.8 L.

6 0
3 years ago
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