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Varvara68 [4.7K]
3 years ago
10

Identifying polar regions within molecules is a very useful skill for chemists that helps us to think about the strength of inte

rmolecular forces and molecular interactions, but it also helps us to understand the chemical properties of substances like acids and bases. here we investigate the molecular structures of the common weak acid, acetic acid, and one of the more common weak bases, methyl amine. acetic acid methyl amine 8th attempt part 1 (1 point)feedbacksee hintsee periodic table what is the molecular formula for acetic acid? $$ part 2 (1 point)feedbacksee hint draw the lewis structure for acetic acid. part 3 (1 point)feedbacksee hint which bond in the acetic acid molecule is the most polar? choose one:
a. o–h bond
b. c–o bond
c. c=o bond
d. c–c bond
e. c–h bond part 4 (1 point)feedbacksee hint what is the molecular formula for methyl amine? $$ part 5 (1 point)feedbacksee hint draw the lewis structure for methyl amine. part 6 (1 point)feedbacksee hint which bond in the methyl amine molecule is the most polar? choose one:
a. c–n bond
b. c–h bond
c. n–h bond
Chemistry
1 answer:
Ilia_Sergeevich [38]3 years ago
4 0
 bond in the acetic acid molecule is the most polar <span>c. c=o bond
</span>which bond in the methyl amine molecule is the most polar <span>c. n–h bond</span>
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Use the formula for second order reaction:

\frac{1}{C} = \frac{1}{C_0} + kt

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1st equation :   \frac{1}{0.56} = \frac{1}{C_0} + 115k

2nd Equation: \frac{1}{0.033} = \frac{1}{C_0} + 735k

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\frac{1}{0.033} = \frac{1}{0.56} - 115k + 735k

\frac{1}{0.033} - \frac{1}{0.56} = 620k

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