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Elina [12.6K]
3 years ago
6

Draw the organic product formed when the structure shown below undergoes reaction with nabr. interactive 3d display mode

Chemistry
1 answer:
olga_2 [115]3 years ago
4 0
Idk sorry i couldn't be no help
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<u>Graphene</u> is a nanomaterial that is often used with other compounds to desalinate and decontaminate water.

The electrical behavior of semiconductor devices and electronics can be engineered using a process called <u>Doping</u>

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3 years ago
Identify which sets of Quantum Numbers are valid for an electron. Each set is ordered (n,ℓ,mℓ,ms).
skad [1K]

3,2,0,1/2

1,0,0,1/2

3,2,2,1/2

4,2,1,1/2

2,1,-1,-1/2

THEY ARE VALID


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_____ can be renewable or nonrenewable
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Energy can be renewable or nonrenewable.
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3 years ago
Why does the moon orbit Earth? <br><br> Select all that apply.
S_A_V [24]

Answer: d

Explanation:

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7 0
2 years ago
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Calculate the amount of heat released when 27.0 g H2O is cooled from a liquid at 314 K to a solid at 263 K. The melting point of
BlackZzzverrR [31]

Answer : The amount of heat released, 45.89 KJ

Solution :

Process involved in the calculation of heat released :

(1):H_2O(l)(314K)\rightarrow H_2O(l)(273K)\\\\(2):H_2O(l)(273K)\rightarrow H_2O(s)(273K)\\\\(3):H_2O(s)(273K)\rightarrow H_2O(s)(263K)

Now we have to calculate the amount of heat released.

Q=[m\times c_{p,l}\times (T_{final}-T_{initial})]+\Delta H_{fusion}+[m\times c_{p,s}\times (T_{final}-T_{initial})]

where,

Q = amount of heat released = ?

m = mass of water = 27 g

c_{p,l} = specific heat of liquid water = 4.184 J/gk

c_{p,s} = specific heat of solid water = 2.093 J/gk

\Delta H_{fusion} = enthalpy change for fusion = 40.7 KJ/mole = 40700 J/mole

conversion : 0^oC=273k

Now put all the given values in the above expression, we get

Q=[27g\times 4.184J/gK\times (314-273)k]+40700J+[27g\times 2.093J/gK\times (273-263)k]

Q=45896.798J=45.89KJ     (1 KJ = 1000 J)

Therefore, the amount of heat released, 45.89 KJ

7 0
3 years ago
Read 2 more answers
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