Answer:
The fraction of kinetic energy lost in the collision is 0.25 .
Explanation:
We know , momentum will be conserved along x direction .
Therefore ,
Now , fraction lost in kinetic energy is :
Therefore , the fraction of kinetic energy lost in the collision is 0.25 .
Because "velocity" means the speed and direction of the motion.
In circular motion, or motion on any curved path, the direction is constantly changing. So even if the speed isn't changing, the <em>velocity</em> is.
Answer:
.y₂ = 0.5704 m
, y2= 44.47 m,
Explanation:,
For this exercise we will use the kinematics relations
Ball
y₁ = y₀ + v₀₁ t
y₀ = 11.0 m
v₀₁ = 5.10 m / s
Pellet
y₂ = 0 + v₀₂ t - ½ g t²
V₀₂ = 39.0 m / s
At the meeting point the two bodies have the same height
y₁ = y₂
y₀ + v₀₁ t = v₀₂ t -1/2 g t²
11 + 5.1 t = 39 t - ½ 9.8 t²
4.9 t² - 33.9 t +11 = 0
.t2 - 6,918 + 2,245 = 0
t = [6,918 ±√ 6,918 2 - 4 2,245)] / 2
t = [6,918 ± 6.2356.] / 2
t₁ = 6.58 s
t₂ = 0.3412 s
Let's calculate the positions for each time
t₂ = 0.3412 s
y₂ = 39 t - ½ 9.8 t2
y₂ = 39 0.3112 - ½ 9.8 0.3412²
y₂ = 0.5704 m
.t1 = 6.58 s
.₂ = 39 6.58 - ½ 9.8 6.58 ^ 2
y2= 44.47 m
That change would most likely cause the current at every point in the circuit
to decrease by 83-1/3% ( 5/6 ) of its original value. Also, the voltage across
each component of the circuit ... resistor, light bulb, motor, open switch etc. ...
would become 5/6 less.
Answer:
Explanation:
The correct answer is Metabolic alkalosis (D). A pH of 7.48 shows slight alkalinity, this normal concentration of Co2 in the blood ranges from 35 mmHg (millimetre Mercury) to 45 mmHg and the normal HCo3 ( Hydrogen trioxo carbonate ion) concentration ranges from 22mEq/L to 26mEq/L.
Therefor the patients pH level is high the Co2 level is normal and the HCo3 level is high. Hence, Metabolic alkalosis