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Akimi4 [234]
3 years ago
8

The power in an electrical circuit is given by the equation P= RR, where /is

Physics
1 answer:
Kobotan [32]3 years ago
4 0

Answer:

The power in an electrical circuit is given by the equation P

The power in an electrical circuit is given by the equation P = I2R, where I is the current flowing through the circuit and R is the resistance of the circui

Explanation:

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Types of mechanical waves include
USPshnik [31]
I think surface waves
4 0
3 years ago
A nonconducting sphere has radius R = 1.29 cm and uniformly distributed charge q = +3.83 fC. Take the electric potential at the
zalisa [80]

Answer:

a) -2.516 × 10⁻⁴ V

b) -1.33 × 10⁻³ V

Explanation:

The electric field inside the sphere can be expressed as:

E= \frac{kqr}{R^3}

The potential at a distance can be represented as:

V(r) - V(0) = -\int\limits^r_0 {\frac{kqr}{R^3} } \, dr^2

V(r) - V(0) = [\frac{qr^2}{8 \pi E_0R^3 }]₀

V(r) =   -[\frac{qr^2}{8 \pi E_0R^3 }]₀

Given that:

q = +3.83 fc = 3.83 × 10⁻¹⁵ C

r = 0.56 cm

 = 0.56 × 10⁻² m

R = 1.29 cm

  =  1.29 × 10⁻² m

E₀ = 8.85 × 10⁻¹² F/m

Substituting our values; we have:

V(r) = -\frac{(3.83*10^{-15}C)(0.560*10^{-2}m)^2}{8 \pi (8.85*10^{-12}F/m)(1.29*10^{-2}m)^3}

V(r) = -2.15  × 10⁻⁴ V

The difference between the radial distance  and center can be expressed as:

V(r) - V(0) = -\int\limits^R_0 {\frac{kqr}{R^3} } \, dr^2

V(r) - V(0) =  [\frac{qr^2}{8 \pi E_0R^3 }]^R

V(r) = -\frac{qR^2}{8 \pi E_0R^3 }

V(r) = -\frac{q}{8 \pi E_0R }

V(r) = -\frac{(3.83*10^{-15}C)}{8 \pi (8.85*10^{-12}F/m)(1.29*10^{-2}m)}

V(r) = -0.00133

V(r) = - 1.33 × 10⁻³ V

8 0
3 years ago
A woman rides a carnival Ferris wheel at radius 20 m, completing 6.0 turns about its horizontal axis every minute. What are (a)
natta225 [31]

Answer:

Explanation:

Given

radius of ferris wheel is 20 m

It completes 6 turns in 1 min

i.e. 1 turn in 10 sec

Therefore its angular velocity is \omega =\frac{2\pi }{10} rad/s

(a)Period of motion is 10 s

Magnitude of centripetal acceleration is \omega ^2r

=\left ( \frac{\pi }{5}\right )^2\times 20=7.89 m/s^2

(b)Highest point will be 40 m

(c) lowest point 0 m i.e. at ground

7 0
3 years ago
NEED HELP ASAP PLEASE!
katrin [286]

Answer:

Here is the solution hope it helps:)

5 0
2 years ago
HELLPPP NOWWA!!!!!!!!!!!!
prisoha [69]

Answer:

b

Explanation:

the gravitational pull also helps with that but

7 0
3 years ago
Read 2 more answers
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