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eimsori [14]
3 years ago
14

When is the kinetic energy of the ball zero and when is it at its highest? When is its potential energy at its lowest and at its

highest? What happens to the kinetic energy and potential energy between point A and point B? (3 points)
Physics
1 answer:
liubo4ka [24]3 years ago
3 0

Answer:

if there is only one planet in the universe and the ball is there it will have 0 kinetic energy if the ball is in the very center of that planet only if the planet itself is absolutely motionless. its at its highest if the planet is moving away from the ball at a slightly faster speed forever. Between point A and B both potential energy and kinetic energy are at perfect 0.

Explanation:

never will have a measurable kinetic or potential energy status unless every single object is included in the calculation.

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A Porsche will always win no matter what
8 0
3 years ago
A spherical capacitor contains a charge of 3.00 nC when connected to a potential difference of 230 V. If its plates are separate
Assoli18 [71]

Answer:

Part(a): the capacitance is 0.013 nF.

Part(b): the radius of the inner sphere is 3.1 cm.

Part(c): the electric field just outside the surface of inner sphere is \bf{2.81 \times 10^{4}~n~C^{-1}}.

Explanation:

We know that if 'a' and 'b' are the inner and outer radii of the shell respectively, 'Q' is the total charge contains by the capacitor subjected to a potential difference of 'V' and '\epsilon_{0}' be the permittivity of free space, then the capacitance (C) of the spherical shell can be written as

C = \dfrac{4 \pi \epsilon_{0}}{(\dfrac{1}{a} - \dfrac{1}{b})}~~~~~~~~~~~~~~~~~~~~~~~~~~~(1)

Part(a):

Given, charge contained by the capacitor Q = 3.00 nC and potential to which it is subjected to is V = 230V.

So the capacitance (C) of the shell is

C &=& \dfrac{Q}{V} = \dfrac{3 \times 10^{-90}~C}{230~V} = 1.3 \times 10^{-11}~F = 0.013~nF

Part(b):

Given the inner radius of the outer shell b = 4.3 cm = 0.043 m. Therefore, from equation (1), rearranging the terms,

&& \dfrac{1}{a} = \dfrac{1}{b} + \dfrac{1}{C/4 \pi \epsilon_{0}} = \dfrac{1}{0.043} + \dfrac{1}{1.3 \times 10^{-11} \times 9 \times 10^{9}} = 31.79\\&or,& a = \dfrac{1}{31.79}~m = 0.031~m = 3.1~cm

Part(c):

If we apply Gauss' law of electrostatics, then

&& E~4 \pi a^{2} = \dfrac{Q}{\epsilon_{0}}\\&or,& E = \dfrac{Q}{4 \pi \epsilon_{0}a^{2}}\\&or,& E = \dfrac{3 \times 10^{-9} \times 9 \times 10^{9}}{0.031^{2}}~N~C^{-1}\\&or,& E = 2.81 \times 10^{4}~N~C^{-1}

3 0
3 years ago
Which planet has a moon with many sulfur volcanoes?
Murljashka [212]

Jupiter i hope it is right answer

6 0
2 years ago
How many signifficant figures do the following number have 258​
Romashka [77]

Answer:

<u>Facts about 258</u>

<u>Sig Figs</u>

3

<u>258</u>

<u>Decimals</u>

0

<u>Scientific Notation</u>

2.58 × 102

<u>E-Notation</u>

2.58e+2

<u>Words</u>

two hundred fifty-eight

Explanation:

258 Rounded to Fewer Sig Figs

2 260                2.6 × 102

1 300           3 × 102

5 0
2 years ago
A ball is projected upward at time t = 0.0 s, from a point on a roof 60 m above the ground. The ball rises, then falls until it
musickatia [10]
<span> y=y0 + vt +1/2gt^2
(solve for t here) cause you know y,y0,v,g
you will do quad formula here

then:
v=v0 +at solve for v
(remember the direction of the ball too (signs))

The main thing to remember here is that when the ball passes exactly (height) where it was launched it will travel the speed at which it was launched. *its almost like the ball was thrown in the downward direction. </span>
7 0
3 years ago
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