Which individual elements make up the following common

Round the mmHg readings to the nearest whole number. Round the kPa readings to the nearest tenth. Round the atm readings to the

Eva8 [605]

i love jesus and i love my mommy

6 0

2 years ago

Which type of acetylcholine receptor is present on postganglionic neurons

Sonja [21]

Answer:

Mescarinic and Nicotinic

Explanation:

Postganglionic fibers can be present in both sympathetic and parasympathetic divisions, their main difference resides in how in the sympathetic division the postganglionic fibers are adrenergic and use norepinephrine (noradrenalin) as a neurotransmitter, in the parasympathetic division, on the other hand, fibers are cholinergic and use acetylcholine as a neurotransmitter, the<em> postganglionic neurons of sweat glands release acetylcholine for the activation of muscarinic receptors, another kind of receptor for acetylcholine are nicotinic receptors </em>that act as transmembrane sodium/potassium channels, while muscarinic receptors need to act through intracellular proteins.

I hope you find this informatiou useful and interesting! Good luck!

4 0

3 years ago

Calculate the wavelength of light emitted when each of the following transitions occur in the hydrogen atom. What type of electr

Alecsey [184]

Answer:

The wavelength of the emitted photon will be approximately 655 nm, which corresponds to the visible spectrum.

Explanation:

In order to answer this question, we need to recall Bohr's formula for the energy of each of the orbitals in the hydrogen atom:

$E_{n} = -\frac{m_{e}e^{4}}{2(4\pi\epsilon_{0})^2\hbar^{2}}\frac{1}{n^2} = E_{1}\frac{1}{n^{2}}$ , where:

[tex]m_{e}[tex] = electron mass

e = electron charge

[tex]\epsilon_{0}[tex] = vacuum permittivity

[tex]\hbar[tex] = Planck's constant over 2pi

n = quantum number

[tex]E_{1}[tex] = hydrogen's ground state = -13.6 eV

Therefore, the energy of the emitted photon is given by the difference of the energy in the 3d orbital minus the energy in the 2nd orbital:

[tex]E_{3} - E_{2} = -13.6 eV(\frac{1}{3^{2}} - \frac{1}{2^{2}})=1.89 eV[tex]

Now, knowing the energy of the photon, we can calculate its wavelength using the equation:

[tex]E = \frac{hc}{\lambda}[tex], where:

E = Photon's energy

h = Planck's constant

c = speed of light in vacuum

[tex]\lambda[tex] = wavelength

Solving for [tex]\lambda[tex] and substituting the required values:

[tex]\lambda = \frac{hc}{E} = \frac{1.239 eV\mu m}{1.89 eV}=0.655\mu m = 655 nm[tex], which correspond to the visible spectrum (The visible spectrum includes wavelengths between 400 nm and 750 nm).

5 0

3 years ago

What molecule(s) could diffuse across the plasma membrane? question 31 options: disaccharides fe2 tryptophan amino acid ch4

nevsk [136]

The molecule that could diffuse across the plasma membrane is methane (CH4).

<h3>What is diffusion?</h3>

Diffusion is the movement of fluids or substances from regions of high concentration toward regions of lower concentration.

The plasma membrane is the semipermeable membrane that surrounds the cytoplasm of a cell. The semipermeability means that it allows some molecules through but blocks other substances.

The semipermeable plasma membrane readily allows the passage of small hydrophobic and polar molecules.

Therefore, the molecule that could diffuse across the plasma membrane is methane (CH4).

Learn more about semipermeability at: brainly.com/question/1652796

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7 0

2 years ago

explain what happens when anhydrous calcium chloride are exposed to the atmosphere for about two days

PtichkaEL [24]

Answer:

Explanation:

Calcium chloride is <u>deliquescent.</u> If exposed to air, it will absorb sufficient water from the air to allow it to dissolve. After a short while, instead of a white lump, you will have a pool of clear liquid.

5 0

3 years ago