Cu = 63.546
N= 14.001 g/mol
O= 15.999 g/mol * 3 = 47.997
Copper (II) Nitrate has a MW of 125.544 g/mol
6.25 x 125.544
= 784.65 <--- is your answer, if there were was a multiple choice or not :)
Answer:
2.107×10²⁴
Explanation:
no of moles=no of particles/Avogadro's number
3.5=X/6.02×10²³
by cross multiplication
3.5×6.02×10²³
=2.107 ×10²⁴
6.3 ×

In scientific notation, the numerical value without the exponent of 10 must be within the range from 1 to just below 10 (for example, 9.99...). In this case, 6.3 is already within this range, so we just have to multiply it by 1. To get a multiplier of 1 using base 10, we would have to raise 10 to the zeroth power.
It depends of the temperature and the pressure. If temperature and pressure are standard 1 mol forms 22.4 liter. So 33.6 liters form 33.6/22.4 = 1.5 mols.
Now calculate the molar mass of carbon dioxide: 12 g/mol + 2x16 g/mol = 44 g/mol
The mass of the 1.5 mols is 1.5mol * 44 g/mol = 66 g.
Answer:
Therefore, the value of K_{p} is 2 \times 10^{9} and value of \Delta G^{o} is -53.2 kJ/mol.
Explanation: